The mass of the belt per unit length in belt drive of pulleys is 10 kg/m. The maximum tension in a belt is 3000 N. The velocity of the belt for maximum power transmission:
10 m/s
In a belt drive system, power is transmitted from one pulley to another by means of a belt. The power transmitted by the belt depends on the tension in the belt and its velocity. There is a specific belt velocity at which the power transmitted is maximum.
The total tension in the tight side of the belt (\(T_1\)) is the sum of the maximum allowable tension (\(T_{max}\)) and the centrifugal tension (\(T_c\)). For maximum power transmission, the condition is that the centrifugal tension must be equal to one-third of the maximum tension.
Given:
The centrifugal tension (\(T_c\)) in a belt is given by the formula:
\(T_c = m v^2\)
where \(v\) is the velocity of the belt.
For maximum power transmission, the centrifugal tension (\(T_c\)) should be one-third of the maximum tension (\(T_{max}\)):
\(T_c = \frac{T_{max}}{3}\)
Substitute the formula for \(T_c\) into the condition for maximum power transmission:
\(m v^2 = \frac{T_{max}}{3}\)
Now, we need to solve for the velocity \(v\):
\(v^2 = \frac{T_{max}}{3m}\)
Take the square root of both sides to find \(v\):
\(v = \sqrt{\frac{T_{max}}{3m}}\)
Substitute the given values of \(T_{max}\) and \(m\) into the equation:
\(v = \sqrt{\frac{3000 \, \text{N}}{3 \times 10 \, \text{kg/m}}}\)
\(v = \sqrt{\frac{3000}{30} \, \text{m}^2/\text{s}^2}\)
\(v = \sqrt{100} \, \text{m/s}\)
\(v = 10 \, \text{m/s}\)
Therefore, the velocity of the belt for maximum power transmission is 10 m/s.
Centrifugal tension is caused by the rotation of the belt. As the belt moves around the pulleys, a centrifugal force acts outwards, creating tension in the belt. This tension adds to the stress on the belt and reduces the effective tension available for transmitting power.
The power transmitted is proportional to the difference between the tension in the tight side and the slack side of the belt, multiplied by the velocity. Including centrifugal tension, the effective tensions become \((T_1 - T_c)\) and \((T_2 - T_c)\), where \(T_1\) and \(T_2\) are the tensions in the tight and slack sides, respectively, due to power transmission alone (excluding centrifugal effect). The condition for maximum power transmission arises from balancing the increase in power due to increased velocity against the decrease in effective tension due to increased centrifugal tension.
In a multiple V belt drive, when a single belt is damaged, it is preferable to change the complete set to _____.
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(Where Tt, Ts, and v are tight side tension, slack side tension and linear velocity of belt respectively)If the tension in tight side and slack side of the belt is 3000 N and 1500 N, respectively. The effective driving force at the circumference of the driven pulley is given by:
The velocity of a belt in belt drive mechanism is 5 m/s. The tension in tight side of belt is 2000 N while the tension in slack side of belt is 1000 N. The power transmitted in the belt drive is: