All Exams Test series for 1 year @ ₹349 only
Question

The marks scored by 100 students in Mathematics examination are given by the following table. Find the mode of this data (up to 2 decimal places).
Marks scored35 - 4445 - 5455 - 6465 - 7475 - 8485 - 94
No. of students10203025105

The correct answer is
61.17

Finding the Mode of Grouped Data

To find the mode of grouped data, we use the formula:

Mode $= L + \frac{f_1 - f_0}{2f_1 - f_0 - f_2} \times h$

Where:

  • $L$ is the lower boundary of the modal class.
  • $f_1$ is the frequency of the modal class.
  • $f_0$ is the frequency of the class preceding the modal class.
  • $f_2$ is the frequency of the class succeeding the modal class.
  • $h$ is the class width.

Data Table and Modal Class Identification

The given data is:

Marks scored 35 - 44 45 - 54 55 - 64 65 - 74 75 - 84 85 - 94
No. of students 10 20 30 25 10 5

The class with the highest frequency (30) is 55 - 64. This is the modal class.

Applying the Mode Formula

From the modal class (55 - 64):

  • The lower limit is 55. Since the class intervals appear inclusive, the lower boundary ($L$) is $55 - 0.5 = 54.5$.
  • The frequency of the modal class ($f_1$) is 30.
  • The frequency of the preceding class (45 - 54) ($f_0$) is 20.
  • The frequency of the succeeding class (65 - 74) ($f_2$) is 25.
  • The class width ($h$) is $(44 - 35 + 1) = 10$.

Calculation Steps

  1. Substitute the values into the mode formula: $ \text{Mode} = 54.5 + \frac{30 - 20}{2 \times 30 - 20 - 25} \times 10 $
  2. Simplify the fraction: $ \text{Mode} = 54.5 + \frac{10}{60 - 20 - 25} \times 10 $ $ \text{Mode} = 54.5 + \frac{10}{15} \times 10 $
  3. Continue the calculation: $ \text{Mode} = 54.5 + \frac{2}{3} \times 10 $ $ \text{Mode} = 54.5 + \frac{20}{3} $ $ \text{Mode} = 54.5 + 6.666... $
  4. Calculate the final value and round to two decimal places: $ \text{Mode} \approx 61.166... $ $ \text{Mode} \approx 61.17 $

The mode of the given data is approximately 61.17.

Was this answer helpful?

Important Questions from Elementary Statistics

  1. In a colony 5 families have 1 child, 7 families have 2 children, 8 families have 3 children and 3 families have 4 children.What is the mode of the number of children.

  2. What will be the difference between mean and median of the given data?

    21, 11, 27, 8, 5, 12, 7, 23, 3, 14, 9, 19
  3. Find the mode and median of 3, 4, 5, 5, 3, 6, 7, 3, 5, 5, 6.

    A. 5 and 5

    B. 3 and 5

    C. 5 and 4

    D. 3 and 4

  4. For which set of numbers do the mean, median and mode all have the same value?

  5. The median of 5, 8, 25, 22, 34, 18 is

Need Expert Advice?

Start Your Preparation with Prepp Mobile App

Download the app from Google Play & App Store
Download the app from Google Play & App Store
Prepp Mobile App