The main cutting force acting on a tool during a turning operation of a metal is 400N. The turning was performed using 2 mm depth of cut and 0.1 mm/rev feed rate. The specific cutting pressure is
The question asks us to find the specific cutting pressure during a turning operation, given the main cutting force, depth of cut, and feed rate. Specific cutting pressure is a key parameter in machining that represents the resistance of the material to cutting.
Specific cutting pressure ($\boldsymbol{k_c}$) is defined as the cutting force ($\boldsymbol{F_c}$) per unit area of the undeformed chip cross-section ($\boldsymbol{A}$).
Mathematically, it is expressed as:
$$k_c = \frac{F_c}{A}$$
The undeformed chip cross-sectional area ($\boldsymbol{A}$) in a turning operation is determined by the depth of cut ($\boldsymbol{d}$) and the feed rate ($\boldsymbol{f}$).
$$A = d \times f$$
Let's identify the given values from the question:
Step 1: Calculate the undeformed chip cross-sectional area ($A$).
Using the formula $A = d \times f$, we plug in the given values:
$$A = (2 \text{ mm}) \times (0.1 \text{ mm/rev})$$
$$A = 0.2 \text{ mm}^2$$
The undeformed chip area is 0.2 square millimeters.
Step 2: Calculate the specific cutting pressure ($k_c$).
Using the formula $k_c = \frac{F_c}{A}$, we plug in the main cutting force and the calculated chip area:
$$k_c = \frac{400 \text{ N}}{0.2 \text{ mm}^2}$$
To simplify the fraction, we can multiply both the numerator and the denominator by 10:
$$k_c = \frac{4000}{2} \text{ N/mm}^2$$
$$k_c = 2000 \text{ N/mm}^2$$
Thus, the specific cutting pressure is 2000 N/mm2.
Let's compare our calculated specific cutting pressure with the given options:
Our calculated value of 2000 N/mm2 matches option 3.
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