The lowest energy of a quantum mechanical one-dimensional simple harmonic oscillator is $300$ cm$^{-1}$. The energy (in cm$^{-1}$) of the next higher level is _________________
The energy levels ($E_n$) of a quantum mechanical one-dimensional simple harmonic oscillator (SHO) are quantized and given by the formula:
$ E_n = \left(n + \frac{1}{2}\right)h\nu $
where $n$ is the quantum number ($n = 0, 1, 2, ...$), $h$ is Planck's constant, and $\nu$ is the characteristic vibrational frequency.
The lowest energy level occurs when $n = 0$, known as the zero-point energy ($E_0$):
$ E_0 = \left(0 + \frac{1}{2}\right)h\nu = \frac{1}{2}h\nu $
We are given that the lowest energy is $E_0 = 300$ cm$^{-1}$.
$ \frac{1}{2}h\nu = 300 \text{ cm}^{-1} $
Therefore, the energy difference between adjacent levels, $h\nu$, is:
$ h\nu = 2 \times 300 \text{ cm}^{-1} = 600 \text{ cm}^{-1} $
This value, $h\nu$, represents the constant energy spacing between consecutive energy levels of the SHO.
The question asks for the energy of the *next higher level*. This corresponds to the state where $n=1$.
The energy of the next level ($E_1$) can be found in two ways:
Both methods yield the same result.
The energy of the next higher level is $900$ cm$^{-1}$.