The length of a simple pendulum is increased four times to its previous value while the mass is doubled. What is the ratio of the new and previous time period of the pendulum?
2:1
Pendulum Time Period Ratio
Given: A simple pendulum's length is increased four times, and its mass is doubled.
Time period of a simple pendulum:
T = 2π √(L / g)
Note: Mass does not affect the time period, so we only consider the length.
Previous time period:
T₁ = 2π √(L / g)
New time period (length = 4L):
T₂ = 2π √(4L / g) = 2π × 2 √(L / g) = 2 T₁
Therefore, the ratio T₂ : T₁ = 2 : 1
Similar Questions
- Consider the following statements :
I. Earthquake waves are basically of two types, namely body waves and surface waves.
II. The body waves interact with the surface rocks and generate surface waves.
Which of the statements given above is/are correct? The frequency (f), wavelength (λ) and speed (v) of a sound wave are related as
Important Questions from Oscillations & Waves
The frequency (f), wavelength (λ) and speed (v) of a sound wave are related as
The length of a simple pendulum is increased four times to its previous value while the mass is doubled. What is the ratio of the new and previous time period of the pendulum?
- Which of the following best describes the shape of a sinusoidal wave signal during one complete cycle?
- Which among the following waves is not an electromagnetic wave?
- In which type of wave do particles of the medium move parallel to the direction of wave propagation?
