The length and breadth of a cuboid are 50 cm and 75 cm, respectively. If the length of the diagonal is $17\sqrt{29}$ cm, then what is the volume (in $cm^{3}$) of the cuboid?
We are given the length and breadth of a cuboid and the length of its diagonal. Our goal is to find the volume of the cuboid.
The relationship between the diagonal ($d$), length ($l$), breadth ($b$), and height ($h$) of a cuboid is given by the formula:
$$d^2 = l^2 + b^2 + h^2$$
First, let's calculate the square of the given diagonal:
$$d^2 = (17\sqrt{29})^2 = 17^2 \times (\sqrt{29})^2 = 289 \times 29$$
Calculating the product:
$$289 \times 29 = 8381$$
So, $d^2 = 8381$ cm$^2$.
Next, let's calculate the squares of the length and breadth:
$$l^2 = 50^2 = 2500 \text{ cm}^2$$
$$b^2 = 75^2 = 5625 \text{ cm}^2$$
Now, substitute these values into the diagonal formula to find $h^2$:
$$8381 = 2500 + 5625 + h^2$$
Combine the known squares:
$$8381 = 8125 + h^2$$
Isolate $h^2$:
$$h^2 = 8381 - 8125$$
$$h^2 = 256 \text{ cm}^2$$
To find the height, take the square root:
$$h = \sqrt{256}$$
$$h = 16 \text{ cm}$$
The volume ($V$) of a cuboid is calculated using the formula:
$$V = l \times b \times h$$
Substitute the known values of length, breadth, and the calculated height:
$$V = 50 \text{ cm} \times 75 \text{ cm} \times 16 \text{ cm}$$
Perform the multiplication:
$$V = (50 \times 75) \times 16$$
$$V = 3750 \times 16$$
$$V = 60000 \text{ cm}^3$$
Therefore, the volume of the cuboid is 60,000 cm$^3$.
Find the total surface area of a closed cylinder having a base radius of 70 m and a height of 110 m. [Use π = \(22\over7\)]
The diameter of the base and slant height of a right circular cone are 30 cm and 113 cm, respectively. Find the volume (in cm³) of the given cone.
(Use $\pi = \frac{22}{7}$)