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Question

The least common multiple of 15x3 y4 and 12x2y5 is:

The correct answer is

60x 3y 5

⇒ 15x3y4 = 3 × 5 × x3 × y4

⇒ 12x2y5 = 2 × 2 × 3 × x2 × y5

∴ LCM of 15x3 yand 12x2y  = 2 × 2 × 3 × 5 × x3 × y5 = 60x3y5

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Important Questions from LCM and HCF

  1. Six bells begin to toll together and toll, respectively, at intervals of 3, 4, 6, 7, 8 and 12 seconds. After how many seconds, will they toll together again?

  2. A and B are two prime numbers such that A > B and their LCM is 209. The value of A 2 - B is:

  3. Find the least number which when divided by 12, 18, 24 and 30 leaves 4 as remainder in each case, but when divided by 7 leaves no remainder.

  4. Calculate the HCF of \(\frac{12}{5}\) \(\frac{14}{15}\)  and  \(\frac{16}{17}\) .

  5. Three numbers are in the proportion of 3 : 8 : 15 and their LCM is 8280. What is their HCF?

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