The least common multiple of 15x3 y4 and 12x2y5 is:
60x 3y 5
⇒ 15x3y4 = 3 × 5 × x3 × y4
⇒ 12x2y5 = 2 × 2 × 3 × x2 × y5
∴ LCM of 15x3 y4 and 12x2y5 = 2 × 2 × 3 × 5 × x3 × y5 = 60x3y5
Six bells begin to toll together and toll, respectively, at intervals of 3, 4, 6, 7, 8 and 12 seconds. After how many seconds, will they toll together again?
A and B are two prime numbers such that A > B and their LCM is 209. The value of A 2 - B is:
Find the least number which when divided by 12, 18, 24 and 30 leaves 4 as remainder in each case, but when divided by 7 leaves no remainder.
Calculate the HCF of \(\frac{12}{5}\) , \(\frac{14}{15}\) and \(\frac{16}{17}\) .
Three numbers are in the proportion of 3 : 8 : 15 and their LCM is 8280. What is their HCF?