I. – COOH
II. – SH
III. – $CH_3$
IV. – CHO
Choose the correct answer from the codes given below :
Chelation is the process where a molecule binds to a central metal ion using two or more donor atoms, forming a ring structure. This ability depends on the presence of functional groups containing atoms with available lone pairs, such as Oxygen (O) or Sulfur (S), capable of coordinating with the metal ion.
Key Chelating Functional Groups Analysis
- Group I: $ - COOH $ (Carboxyl group): This group contains oxygen atoms. The deprotonated carboxylate form ($ - COO^- $) is an effective ligand that coordinates with metal ions, forming stable chelate rings.
- Group II: $ - SH $ (Thiol group): The sulfur atom in the thiol group possesses lone pair electrons and can readily coordinate with various metal ions, especially transition metals. Deprotonation to the thiolate ($ - S^- $) increases its coordinating ability.
- Group III: $ - CH_3 $ (Methyl group): This is a simple alkyl group. It lacks electronegative atoms with available lone pairs and does not have the capacity to coordinate with metal ions, thus it is not involved in chelation.
- Group IV: $ - CHO $ (Aldehyde group): The carbonyl oxygen atom ($ C=O $) in the aldehyde group can participate in coordination with metal ions, contributing to the chelation process.
Based on this analysis, functional groups I ($ - COOH $), II ($ - SH $), and IV ($ - CHO $) possess the necessary coordinating atoms (O and S) required for effective chelation of metal ions. Group III ($ - CH_3 $) does not.
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