The initial state of $Q_3Q_2Q_1Q_0$ in the digital circuit shown below is $1011$. The new value of $Q_3Q_2Q_1Q_0$ after two rising edges of the clock (CLK) will be _____.
To solve this problem, we need to understand how the given digital circuit works. The circuit involves flip-flops with feedback, which likely functions as a shift register.
The initial state of the circuit is \(Q_3Q_2Q_1Q_0 = 1011\).
- Upon the first rising edge of the clock (CLK), each flip-flop will capture the value present at its D input. In shift registers, the value from one flip-flop is passed to the next on every clock pulse. Therefore:
- Flip-flop \(Q_0\) captures the feedback value from \(Q_3\), which is 1.
- Flip-flop \(Q_1\) captures the value from \(Q_0\), which is 1.
- Flip-flop \(Q_2\) captures the value from \(Q_1\), which is 0.
- Flip-flop \(Q_3\) captures the value from \(Q_2\), which is 1.
- On the second rising edge of the clock:
- Flip-flop \(Q_0\) captures the value from \(Q_3\), which is 1.
- Flip-flop \(Q_1\) captures the value from \(Q_0\), which is 1.
- Flip-flop \(Q_2\) captures the value from \(Q_1\), which is 0.
- Flip-flop \(Q_3\) captures the value from \(Q_2\), which is 1.
Thus, after two rising edges of the clock, the new value of \(Q_3Q_2Q_1Q_0\) is 1010.
Important Questions from Shift Register Counters
The number of unused states in a n-bit Johnson Counter is:
Depending on the counter, there are up to _________ modes available on high-speed counters.
If the registers have both shifts and parallel load capabilities, they are referred as _________.
The highest speed counter is
A Shift register in which the output of the last flip-flop is connected to the input of the first flip-flop
