The incidence matrix of the graph shown
\(\begin{bmatrix} 1 & 0 & 0 & 0 & 1 \\ -1 & 1 & 0 & 1 & 0 \\ 0 & -1 & 1 & 0 & 0 \\ 0 & 0 & -1 & -1 & -1 \end{bmatrix}\)
The provided question requires determining the incidence matrix of the given directed graph. The incidence matrix is a way of representing a directed graph using a matrix. Each row of the matrix corresponds to a vertex, and each column corresponds to an edge. The elements of the matrix are typically 0, 1, or -1:
From the diagram, we can number the edges as follows:
Based on this, we can construct the incidence matrix as:
| Edge 1 | Edge 2 | Edge 3 | Edge 4 | Edge 5 | |
|---|---|---|---|---|---|
| Vertex 1 | 1 | 0 | 0 | 0 | 1 |
| Vertex 2 | -1 | 1 | 0 | 1 | 0 |
| Vertex 3 | 0 | -1 | 1 | 0 | 0 |
| Vertex 4 | 0 | 0 | -1 | -1 | -1 |
Therefore, the correct incidence matrix is:
\(\begin{bmatrix} 1 & 0 & 0 & 0 & 1 \\ -1 & 1 & 0 & 1 & 0 \\ 0 & -1 & 1 & 0 & 0 \\ 0 & 0 & -1 & -1 & -1 \end{bmatrix}\)
This matches the given correct option.
A principal node is a
Which of the following statement(s) is/are correct regarding about the undirected graph?
I. Number of odd degree vertices is even.
II. Sum of degrees of all vertices is even.
Let $G(V, E)$ be an undirected and unweighted graph with 100 vertices. Let $d(u, v)$ denote the number of edges in a shortest path between vertices $u$ and $v$ in $V$. Let the maximum value of $d(u, v)$, $u, v \in V$ such that $u \neq v$, be 30. Let T be any breadth-first-search tree of G. Which ONE of the given options is CORRECT for every such graph G?