The HCF of 36, 45 and 54 is ______.
9
To find the Highest Common Factor (HCF) of 36, 45, and 54, we can use the prime factorization method.
First, let's find the prime factorization of each number:
- 36 = 22 × 32
- 45 = 32 × 5
- 54 = 2 × 33
The HCF is found by identifying the common prime factors with the lowest powers and multiplying them together. In this case, the only common prime factor is 3. The lowest power of 3 present in the factorizations is 32 = 9.
Therefore, the HCF of 36, 45, and 54 is 9.
Important Questions from LCM and HCF
Six bells begin to toll together and toll, respectively, at intervals of 3, 4, 6, 7, 8 and 12 seconds. After how many seconds, will they toll together again?
A and B are two prime numbers such that A > B and their LCM is 209. The value of A 2 - B is:
Find the least number which when divided by 12, 18, 24 and 30 leaves 4 as remainder in each case, but when divided by 7 leaves no remainder.
Calculate the HCF of \(\frac{12}{5}\) , \(\frac{14}{15}\) and \(\frac{16}{17}\) .
Three numbers are in the proportion of 3 : 8 : 15 and their LCM is 8280. What is their HCF?
