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Question

The haplace's equation in spherical polar coordinates is :

The correct answer is

$ [\frac{\partial}{\partial r} (\frac{1}{r^2} \frac{\partial U}{\partial r}) + \frac{1}{\sin \theta} \frac{\partial}{\partial \theta} (\sin \theta \frac{\partial U}{\partial \theta}) + \frac{1}{ \sin^2 \theta} \frac{\partial^2 U}{\partial \phi^2}] \frac{1}{r^2}= 0 $

The given question asks for the Laplace's equation in spherical polar coordinates. In mathematical physics, the Laplace equation is a second-order partial differential equation often encountered in various fields such as electrostatics, fluid dynamics, and quantum mechanics. Its general form is:

\(\nabla^2 U = 0\)

where \(U\) is a scalar potential function.

In spherical polar coordinates (r, \theta, \phi), the Laplacian takes the form:

\[\nabla^2 U = \frac{1}{r^2}\frac{\partial}{\partial r}\left(r^2 \frac{\partial U}{\partial r}\right) + \frac{1}{r^2 \sin \theta}\frac{\partial}{\partial \theta} \left(\sin \theta \frac{\partial U}{\partial \theta}\right) + \frac{1}{r^2 \sin^2 \theta} \frac{\partial^2 U}{\partial \phi^2} = 0\]

Analyzing the options given:

  • Option 1: This considers the division by r^2, consistent with the Laplacian in this coordinate system.
  • Option 2: Divides by r, which is not consistent with the spherical polar Laplacian.
  • Option 3: Also divides by r, similarly incorrect.
  • Option 4: Matches our derived expression for the Laplace's equation in spherical coordinates, with division by r^2.

Conclusion: The correct answer is Option 4, which accurately represents the Laplace equation in spherical polar coordinates:

\[\left[\frac{\partial}{\partial r} \left(\frac{1}{r^2} \frac{\partial U}{\partial r}\right) + \frac{1}{\sin \theta} \frac{\partial}{\partial \theta} \left(\sin \theta \frac{\partial U}{\partial \theta}\right) + \frac{1}{\sin^2 \theta} \frac{\partial^2 U}{\partial \phi^2}\right] \frac{1}{r^2}= 0\]
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