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Question

The half-life period of a radioactive element is 140 days. After 560 days, 1 g of the element will reduce to

The correct answer is

1/16 g

Radioactive Element Half-Life Explained

This question deals with the concept of radioactive decay, specifically how the amount of a radioactive substance changes over time based on its half-life period. The half-life is the time it takes for half of the radioactive atoms in a sample to decay.

Calculating Radioactive Decay Over Time

We are given:

  • Initial amount of the radioactive element: 1 g
  • The half-life period ($T_{1/2}$): 140 days
  • The total time elapsed ($t$): 560 days

To find out how much of the element remains after 560 days, we first need to determine how many half-lives have occurred during this period.

Determining the Number of Half-Lives

The number of half-lives ($n$) can be calculated using the formula:

$$ n = \frac{t}{T_{1/2}} $$

Substituting the given values:

$$ n = \frac{560 \text{ days}}{140 \text{ days}} $$

$$ n = 4 $$

So, 4 half-lives have passed.

Calculating the Remaining Amount of the Element

After each half-life, the amount of the radioactive element reduces by half. The remaining amount can be calculated using the formula:

$$ \text{Remaining Amount} = \text{Initial Amount} \times \left(\frac{1}{2}\right)^n $$

Using the initial amount of 1 g and the calculated number of half-lives ($n=4$):

$$ \text{Remaining Amount} = 1 \text{ g} \times \left(\frac{1}{2}\right)^4 $$

First, calculate $\left(\frac{1}{2}\right)^4$:

$$ \left(\frac{1}{2}\right)^4 = \frac{1^4}{2^4} = \frac{1}{16} $$

Now, multiply this by the initial amount:

$$ \text{Remaining Amount} = 1 \text{ g} \times \frac{1}{16} $$

$$ \text{Remaining Amount} = \frac{1}{16} \text{ g} $$

Therefore, after 560 days, 1 g of the radioactive element will reduce to 1/16 g.

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Important Questions from Radioactivity

  1. The energies of the 3 lowest states of an atom are E 0 = −14 eV, E 1  = −9 eV and E 2  = −7 eV. The Einstein coefficients are A 10  = 3 × 10 8  s −1 , A 20  = 1.2 × 10 8  s −1  and A 21  = 8 × 10 7  s −1 . If a large number of atoms are in the energy level E 2 , the mean radiative lifetime of this excited state is
  2. The nuclei of 137 Cs decay by the emission of β - particles with a half life of 30.08 years. The activity (in units of disintegrations per second or Bq) of a 1 mg source of 137 Cs, prepared on January 1, 1980, as measured on January 1, 2021 is closest to

  3. The Q - value of the α - decay of 232 Th to the ground state of 228 Ra is 4082 keV. The maximum possible kinetic energy of the α - particle is closest to

  4. Radioactivity is the characteristic of which of the following?

  5. Particles which can be added to the nucleus of an atom without changing its chemical properties are

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