The half-life period of a radioactive element is 140 days. After 560 days, 1 g of the element will reduce to
1/16 g
This question deals with the concept of radioactive decay, specifically how the amount of a radioactive substance changes over time based on its half-life period. The half-life is the time it takes for half of the radioactive atoms in a sample to decay.
We are given:
To find out how much of the element remains after 560 days, we first need to determine how many half-lives have occurred during this period.
The number of half-lives ($n$) can be calculated using the formula:
$$ n = \frac{t}{T_{1/2}} $$
Substituting the given values:
$$ n = \frac{560 \text{ days}}{140 \text{ days}} $$
$$ n = 4 $$
So, 4 half-lives have passed.
After each half-life, the amount of the radioactive element reduces by half. The remaining amount can be calculated using the formula:
$$ \text{Remaining Amount} = \text{Initial Amount} \times \left(\frac{1}{2}\right)^n $$
Using the initial amount of 1 g and the calculated number of half-lives ($n=4$):
$$ \text{Remaining Amount} = 1 \text{ g} \times \left(\frac{1}{2}\right)^4 $$
First, calculate $\left(\frac{1}{2}\right)^4$:
$$ \left(\frac{1}{2}\right)^4 = \frac{1^4}{2^4} = \frac{1}{16} $$
Now, multiply this by the initial amount:
$$ \text{Remaining Amount} = 1 \text{ g} \times \frac{1}{16} $$
$$ \text{Remaining Amount} = \frac{1}{16} \text{ g} $$
Therefore, after 560 days, 1 g of the radioactive element will reduce to 1/16 g.
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