The half life of a radioactive substance is 10 years and its initial mass is 1 g. The remaining amount after 20 years is ________.
0.25 g
The concept of half-life is fundamental in understanding the decay of radioactive substances. It represents the time required for half of the radioactive nuclei in a sample to undergo decay.
To determine the remaining amount of a radioactive substance after a certain period, we first need to find out how many half-lives have passed during that time. The question states that the half-life ($\(T_{1/2}\)$) is 10 years and the total time ($\(t\)$) elapsed is 20 years.
The number of half-lives ($\(n\)$) is calculated using the formula:
\[n = \frac{\text{Total time }(t)}{\text{Half-life }(T_{1/2})}\]
Substituting the given values:
\[n = \frac{20 \text{ years}}{10 \text{ years}} = 2 \text{ half-lives}\]
This means that the substance has undergone decay through two half-life periods.
The initial mass of the radioactive substance is given as 1 g. We need to find the remaining amount after 2 half-lives. The general formula to calculate the remaining amount ($\(N\)$) after 'n' half-lives from an initial amount ($\(N_0\)$) is:
\[N = N_0 \left(\frac{1}{2}\right)^n\]
Here, \(N_0 = 1 \text{ g}\) and \(n = 2\).
Substituting these values into the formula:
\[N = 1 \text{ g} \times \left(\frac{1}{2}\right)^2\]
\[N = 1 \text{ g} \times \left(\frac{1}{4}\right)\]
\[N = 0.25 \text{ g}\]
Alternatively, we can track the decay step-by-step:
| Time Elapsed | Number of Half-Lives | Remaining Mass |
|---|---|---|
| Initial (0 years) | 0 | 1 g |
| After 10 years | 1 | $\(1 \text{ g} \times \frac{1}{2} = 0.5 \text{ g}\)$ |
| After 20 years | 2 | $\(0.5 \text{ g} \times \frac{1}{2} = 0.25 \text{ g}\)$ |
Therefore, after 20 years, the remaining amount of the radioactive substance is 0.25 g.
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