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Question

The greatest prime factor of $(3^{199} – 3^{196})$ is

The correct answer is
13

Factorization of Expression

We need to find the greatest prime factor of the expression $(3^{199} – 3^{196})$. First, factor out the common term, which is the lowest power of 3, $3^{196}$.

$3^{199} – 3^{196} = 3^{196} (3^{199-196} – 1)$

Simplifying the Expression

Now, simplify the term inside the parenthesis:

$3^{196} (3^3 – 1)$

Calculate $3^3$:

$3^3 = 3 \times 3 \times 3 = 27$

Substitute this back into the expression:

$3^{196} (27 – 1) = 3^{196} \times 26$

Prime Factorization

To find the greatest prime factor, we determine the prime factors of the simplified expression $3^{196} \times 26$.

  • The prime factors of $3^{196}$ consist only of the prime number 3.
  • Find the prime factors of 26: $26 = 2 \times 13$. Both 2 and 13 are prime numbers.

The prime factors of the entire expression $(3^{199} – 3^{196})$ are therefore 3, 2, and 13.

Greatest Prime Factor Identification

Comparing the prime factors {2, 3, 13}, the largest number is 13.

Thus, the greatest prime factor of $(3^{199} – 3^{196})$ is 13.

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Important Questions from Integers

  1. Find the value of \(\sqrt{2025}\) .

  2. How many times does the number 5 occur in the range of numbers from 1 to 100?

    A. 21

    B. 22

    C. 20

    D. 19

  3. A prime number

    A. is not a positive integer.

    B. has no divisor at all.

    C. has only 1 and itself as divisors.

    D. has more than two divisors.

  4. __________ are twin prime number.

    A. (4, 9)

    B. (2, 3)

    C. (4, 6)

    D. (3, 5)
  5. A factory produced 18,58,509 cassettes in the month of January, 7623 more cassettes in the of February and owing to short supply of electricity produced 25,838 less cassettes in March than in February. Find the total production in all?

    A. 55,57,312

    B. 59,83,245

    C. 55,64,935

    D. 56,08,988
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