We need to find the greatest prime factor of the expression $(3^{199} – 3^{196})$. First, factor out the common term, which is the lowest power of 3, $3^{196}$.
$3^{199} – 3^{196} = 3^{196} (3^{199-196} – 1)$
Now, simplify the term inside the parenthesis:
$3^{196} (3^3 – 1)$
Calculate $3^3$:
$3^3 = 3 \times 3 \times 3 = 27$
Substitute this back into the expression:
$3^{196} (27 – 1) = 3^{196} \times 26$
To find the greatest prime factor, we determine the prime factors of the simplified expression $3^{196} \times 26$.
The prime factors of the entire expression $(3^{199} – 3^{196})$ are therefore 3, 2, and 13.
Comparing the prime factors {2, 3, 13}, the largest number is 13.
Thus, the greatest prime factor of $(3^{199} – 3^{196})$ is 13.
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