The gas which turns lime water milky is:
Carbon dioxide
The question asks about a specific chemical test used to identify a gas that turns lime water milky. This is a common and important test in chemistry.
Lime water is simply the common name for a dilute aqueous solution of calcium hydroxide, with the chemical formula \( \text{Ca(OH)}_2 \). It is a clear, colorless liquid.
When carbon dioxide gas (\( \text{CO}_2 \)) is passed through lime water, a chemical reaction occurs. Carbon dioxide reacts with the calcium hydroxide to form calcium carbonate (\( \text{CaCO}_3 \)). Calcium carbonate is a solid substance that does not dissolve in water; it is insoluble. This insoluble solid forms tiny particles that are suspended in the solution, making it appear cloudy or milky.
The chemical equation for this reaction is:
\( \text{Ca(OH)}_2\text{(aq)} + \text{CO}_2\text{(g)} \rightarrow \text{CaCO}_3\text{(s)} + \text{H}_2\text{O(l)} \)
Here:
The formation of the solid calcium carbonate is what causes the milky appearance in the lime water.
Therefore, among the given options, only carbon dioxide gas reacts with lime water in a way that produces an insoluble precipitate (calcium carbonate), leading to the characteristic milky appearance.
The gas that turns lime water milky is carbon dioxide.
| Gas | Common Test | Observation |
|---|---|---|
| Hydrogen (\( \text{H}_2 \)) | Bring a burning splinter near the gas | Burns with a 'pop' sound |
| Oxygen (\( \text{O}_2 \)) | Bring a glowing splinter into the gas | Relights the glowing splinter |
| Carbon dioxide (\( \text{CO}_2 \)) | Pass the gas through lime water | Lime water turns milky |
It's important to note what happens if you pass an excess amount of carbon dioxide through the milky lime water. Initially, the milky precipitate of calcium carbonate forms:
\( \text{CaCO}_3\text{(s)} + \text{H}_2\text{O(l)} + \text{CO}_2\text{(g)} \rightarrow \text{Ca(HCO}_3\text{)}_2\text{(aq)} \)
When excess carbon dioxide is passed, the insoluble calcium carbonate reacts further with water and carbon dioxide to form calcium bicarbonate (\( \text{Ca(HCO}_3\text{)}_2 \)), which is soluble in water. This reaction causes the milky solution to turn clear again.
So, the milky appearance due to carbon dioxide is temporary if the gas is passed in excess.
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I. Methane
II. Nitrous oxide
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