Question
The gain of a CE amplifier is highest at
The correct answer is
mid frequencies
CE Amplifier Gain Analysis by Frequency
The gain of a Common Emitter (CE) amplifier is not constant across all frequencies. Its frequency response curve typically shows three distinct regions:
- Low Frequencies: Gain is reduced due to the effects of coupling capacitors and bypass capacitors. These components act as impedances that increase with decreasing frequency, forming voltage dividers that lower the effective gain.
- Mid Frequencies: In this range, the reactive effects of capacitors (coupling, bypass, and parasitic) are negligible. The amplifier behaves closest to its theoretical ideal, resulting in the highest and relatively constant voltage gain. This is the intended operating range for maximum amplification.
- High Frequencies: Gain decreases significantly as parasitic capacitances (like junction capacitances and the Miller effect) become dominant. These capacitances create shunt paths for the signal, reducing the effective gain.
Therefore, the gain of a CE amplifier is highest in the mid frequencies range.
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Important Questions from Configuration of BJT
BC147 is the transistor used for:
- What is the relationship between the common-emitter current gain ($\beta$) and the common-base current gain ($\alpha$) of a bipolar junction transistor (BJT)?
Which of the following is NOT true for a common collector transistor?
The other name for the common collector amplifier is -
Match List I with List II:
List I
(Bias Configuration of BJT)
List II
(Stability factor equation)
(A) Fixed Bias Configuration (I) S(V BE ) = \(\rm −\frac{\beta/R_E}{\beta+R_{TH}/R_E}\) (B) Emitter Bias Configuration (II) S(V BE ) = −β/R E (C) Voltage Divider Configuration (III) S(V BE ) = \(\rm −\frac{\beta/R_C}{\beta+R_E/R_C}\) (D) Feedback Bias Configuration (IV) S(V BE ) = \(\rm −\frac{\beta/R_E}{\beta+R_B/R_E}\) Choose the correct answer from the options given below :
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