The peak factor of a sinusoidal waveform is:
1.414
The question asks for the peak factor of a sinusoidal waveform. Let's break down what this means and how to calculate it.
The peak factor, also known as the crest factor, is a dimensionless measure used in electrical engineering to describe the characteristics of an alternating current (AC) waveform. It is defined as the ratio of the peak (or maximum) value of the waveform to its RMS (Root Mean Square) value.
Mathematically, the peak factor (PF) is expressed as:
$$ \text{Peak Factor} = \frac{\text{Peak Value}}{\text{RMS Value}} $$
Consider a sinusoidal voltage waveform given by the equation:
$$ v(t) = V_{peak} \sin(\omega t) $$
Where:
For any sinusoidal waveform, the RMS value is related to the peak value by the following formula:
$$ V_{RMS} = \frac{V_{peak}}{\sqrt{2}} $$
Now, we can substitute these values into the peak factor formula:
$$ \text{Peak Factor} = \frac{V_{peak}}{V_{RMS}} = \frac{V_{peak}}{\frac{V_{peak}}{\sqrt{2}}} $$
Simplifying the expression, we get:
$$ \text{Peak Factor} = \sqrt{2} $$
The square root of 2 ($ \sqrt{2} $) is approximately equal to 1.414.
Let's look at the options provided:
Therefore, the correct peak factor for a sinusoidal waveform is $ \sqrt{2} $, which is approximately 1.414.
The peak factor quantifies how much the peak of a waveform exceeds its RMS value. For the standard sinusoidal waveform, this ratio is consistently $ \sqrt{2} $, approximately 1.414.
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