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Question

The following reaction depicts the activity of a particular class of enzymes :
$$ \begin{array}{cc} \text{X} & \text{Y} \\ | & | \\ \text{C} - & \text{C} \end{array} \xrightarrow{E} \text{X} - \text{Y} + \text{C} = \text{C} $$
(Substrate) $\quad$ (Product) (Product)
Identify the enzyme class 'E' from the following options :

This question was previously asked in
NEET UG Re-Exam 2026 Question Paper (21-Jun-2026)
The correct answer is
Lyases

Enzyme Class Identification: Lyase Activity

The reaction shows enzyme 'E' acting on a substrate containing a $\text{C} - \text{C}$ single bond.

The products include a $\text{C} = \text{C}$ double bond and the combined $\text{X} - \text{Y}$ molecule.

Key Characteristics of Lyases:

  • Lyases catalyze the breaking of chemical bonds via elimination reactions.
  • This often results in the formation of a double bond (e.g., $\text{C} = \text{C}$) or a ring structure.
  • These reactions occur without hydrolysis or oxidation.

The observed formation of the $\text{C} = \text{C}$ double bond directly matches the defining activity of Lyases.

Other enzyme classes do not fit this reaction pattern:

  • Ligases join molecules.
  • Transferases move functional groups.
  • Isomerases rearrange atoms within a molecule.

Therefore, enzyme 'E' belongs to the class Lyases.

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