The focal length of a mirror is f. If it is placed in water (n = 4/3), its focal length will be:
f
The focal length of a mirror is a property that describes how strongly the mirror converges or diverges light rays. For a spherical mirror, the focal length ($f$) is defined as half of its radius of curvature ($R$).
The relationship is given by:
$$f = \frac{R}{2}$$
This relationship is based purely on the geometry of the mirror's surface. The radius of curvature ($R$) is the radius of the sphere from which the mirror surface is a part.
Optical components interact with light. When light passes from one medium to another (like from air to water), it changes speed. This change in speed causes refraction, which is the bending of light.
For lenses, which work based on the principle of refraction, the focal length significantly depends on the refractive index of the lens material and the refractive index of the surrounding medium. The lens maker's formula clearly shows this dependency:
$$\frac{1}{f} = (n_{lens/medium} - 1) \left(\frac{1}{R_1} - \frac{1}{R_2}\right)$$
Here, $n_{lens/medium}$ is the refractive index of the lens material relative to the surrounding medium. If the medium changes, $n_{lens/medium}$ changes, and thus the focal length ($f$) of the lens changes.
Mirrors work based on the principle of reflection, not refraction. When light hits the surface of a mirror, it bounces back into the same medium. The laws of reflection (angle of incidence equals angle of reflection) do not depend on the refractive index of the medium in which the mirror is placed.
The focal length of a mirror is determined solely by its curvature (radius of curvature). Since placing the mirror in water does not change its physical shape or curvature, its focal length remains unaffected by the surrounding medium.
Let's summarize the key difference:
Therefore, if a mirror with focal length $f$ in air is placed in water (with refractive index $n = 4/3$), its focal length will remain unchanged.
The focal length of the mirror in water will still be $f$.
The focal length of a mirror depends only on its radius of curvature. Placing a mirror in water does not alter its physical shape or its radius of curvature. Therefore, the focal length of the mirror remains the same.
The number of images observable between two parallel mirror is
Which of the following pair is correct?
I. Mirror formula : (1/v) – (1/u) = (1/f)
II. Lens formula : (1/v) + (1/u) = (1/f)
A ray of light is made incident on a concave mirror, parallel to its principal axis. After reflection it will -