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Question

The feed rate of single point cutting tool is 3 mm/revolution and the workpiece is rotating at 600 r.p.m. Determine the total machining time to turn the cylindrical surface of length 300 mm of the workpiece.

The correct answer is

10 sec

Machining Time Calculation for Turning

This question asks us to determine the total machining time required to turn a cylindrical surface using a single point cutting tool. We are given the feed rate, workpiece rotation speed, and the length of the surface to be machined.

Given Parameters

  • Feed rate ($f$) = 3 mm/revolution
  • Workpiece rotation speed ($N$) = 600 r.p.m. (revolutions per minute)
  • Length of workpiece surface to be turned ($L$) = 300 mm

Calculating Machining Time

The total machining time ($T$) for turning a cylindrical surface with a single pass can be calculated using the formula:

$$T = \frac{L}{f \times N}$$

Where:

  • $T$ is the machining time
  • $L$ is the length of the cut (length of the workpiece surface)
  • $f$ is the feed rate
  • $N$ is the rotation speed of the workpiece

Let's substitute the given values into the formula:

$$T = \frac{300 \text{ mm}}{3 \text{ mm/revolution} \times 600 \text{ revolutions/minute}}$$

First, calculate the product of feed rate and rotation speed, which gives the feed speed (the distance the tool travels along the workpiece per minute):

Feed speed = $f \times N = 3 \text{ mm/revolution} \times 600 \text{ revolutions/minute} = 1800 \text{ mm/minute}$

Now substitute this back into the machining time formula:

$$T = \frac{300 \text{ mm}}{1800 \text{ mm/minute}}$$

$$T = \frac{300}{1800} \text{ minutes}$$

$$T = \frac{1}{6} \text{ minutes}$$

Converting Time to Seconds

The options are given in seconds. We need to convert the calculated time from minutes to seconds. There are 60 seconds in 1 minute.

$$T = \frac{1}{6} \text{ minutes} \times 60 \text{ seconds/minute}$$

$$T = 10 \text{ seconds}$$

Therefore, the total machining time required to turn the cylindrical surface is 10 seconds.

Summary

Given:

  • Feed rate ($f$) = 3 mm/rev
  • Speed ($N$) = 600 rpm
  • Length ($L$) = 300 mm

Formula:

$$T = \frac{L}{f \times N}$$

Calculation:

$$T = \frac{300 \text{ mm}}{(3 \text{ mm/rev}) \times (600 \text{ rev/min})} = \frac{300 \text{ mm}}{1800 \text{ mm/min}} = \frac{1}{6} \text{ min}$$

Convert to seconds:

$$T = \frac{1}{6} \text{ min} \times 60 \text{ sec/min} = 10 \text{ seconds}$$

The calculated machining time of 10 seconds matches one of the provided options.

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Important Questions from Metal Cutting Processes

  1. Excessive heat generated during metal cutting is due to

  2. During metal cutting, low feed and high cutting speed is considered to obtain ________.

  3. ______ is the process used for applying a protective finish to metallic objects.

  4. Most suitable cutting fluid for low and medium speed machining of Grey cast iron is

  5. The cutting speed of the tool in turning operation is:

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