The expression \(\frac{{\left( {x + y} \right) - \left| {x - y} \right|}}{2}\) is equal to
the minimum of x and y
We are asked to simplify the given algebraic expression:
$$ E = \frac{{\left( {x + y} \right) - \left| {x - y} \right|}}{2} $$
To simplify this expression, we need to consider the definition of the absolute value function, \( |a| \), which is:
In our expression, the absolute value term is \( |x - y| \). We will analyze this based on the relationship between \( x \) and \( y \).
If \( x \) is greater than or equal to \( y \), then \( x - y \ge 0 \). According to the definition of absolute value:
$$ |x - y| = x - y $$
Now, substitute this back into the original expression \( E \):
$$ E = \frac{{\left( {x + y} \right) - \left( {x - y} \right)}}{2} $$
Simplify the numerator:
$$ E = \frac{x + y - x + y}{2} $$
$$ E = \frac{2y}{2} $$
$$ E = y $$
Since we assumed \( x \ge y \), the value \( y \) represents the minimum of \( x \) and \( y \). Thus, in this case, \( E = \min(x, y) \).
If \( x \) is less than \( y \), then \( x - y < 0 \). According to the definition of absolute value:
$$ |x - y| = -(x - y) = y - x $$
Now, substitute this back into the original expression \( E \):
$$ E = \frac{{\left( {x + y} \right) - \left( {y - x} \right)}}{2} $$
Simplify the numerator:
$$ E = \frac{x + y - y + x}{2} $$
$$ E = \frac{2x}{2} $$
$$ E = x $$
Since we assumed \( x < y \), the value \( x \) represents the minimum of \( x \) and \( y \). Thus, in this case, \( E = \min(x, y) \).
In both possible cases (\( x \ge y \) and \( x < y \)), the expression simplifies to the minimum value between \( x \) and \( y \).
Therefore, the expression \( \frac{{\left( {x + y} \right) - \left| {x - y} \right|}}{2} \) is equal to the minimum of \( x \) and \( y \).
This corresponds to Option 2.
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