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Question

The expression for the transconductance (g m) of a JFET is:

The correct answer is \(\rm g_m=g_{mo}\left[ 1- \left(\frac{V_{GS}}{V_P}\right) \right]\)

JFET Transconductance Expression Explained

The Junction Field-Effect Transistor (JFET) is a voltage-controlled device where the voltage applied to the gate-source junction controls the drain current. One of the key parameters that describes the operational characteristics of a JFET is its transconductance, denoted as gm.

Understanding JFET Transconductance

Transconductance (gm) for a JFET is a measure of how effectively the gate-source voltage (VGS) controls the drain current (ID). It is defined as the change in drain current for a given change in gate-source voltage, while keeping the drain-source voltage (VDS) constant. Mathematically, it is expressed as:

$g_m = \left. \frac{\partial I_D}{\partial V_{GS}} \right|_{V_{DS} = \text{constant}}$

The drain current (ID) in the saturation region of a JFET is described by the Shockley equation:

$I_D = I_{DSS} \left( 1 - \frac{V_{GS}}{V_P} \right)^2$

  • IDSS: Drain-to-source saturation current with gate shorted to source (VGS = 0 V). This is the maximum drain current.
  • VGS: Gate-source voltage.
  • VP: Pinch-off voltage. This is the gate-source voltage at which the drain current becomes zero.

Deriving the JFET Transconductance Formula

To find the expression for gm, we differentiate the Shockley equation with respect to VGS:

$g_m = \frac{\partial}{\partial V_{GS}} \left[ I_{DSS} \left( 1 - \frac{V_{GS}}{V_P} \right)^2 \right]$

Applying the chain rule for differentiation:

$g_m = I_{DSS} \cdot 2 \left( 1 - \frac{V_{GS}}{V_P} \right) \cdot \frac{\partial}{\partial V_{GS}} \left( 1 - \frac{V_{GS}}{V_P} \right)$

$g_m = I_{DSS} \cdot 2 \left( 1 - \frac{V_{GS}}{V_P} \right) \cdot \left( -\frac{1}{V_P} \right)$

$g_m = -\frac{2 I_{DSS}}{V_P} \left( 1 - \frac{V_{GS}}{V_P} \right)$

For N-channel JFETs, VP is a negative value. To ensure gm is a positive quantity, we consider the magnitude of \( \left( -\frac{2 I_{DSS}}{V_P} \right) \).

The maximum transconductance, gmo, occurs when VGS = 0 V. Substituting VGS = 0 into the derived gm expression:

$g_{mo} = -\frac{2 I_{DSS}}{V_P} \left( 1 - \frac{0}{V_P} \right) = -\frac{2 I_{DSS}}{V_P}$

Now, substitute the expression for gmo back into the equation for gm:

$g_m = g_{mo} \left( 1 - \frac{V_{GS}}{V_P} \right)$

This is the standard expression for the transconductance of a JFET.

Analyzing the Options for JFET Transconductance

Let's evaluate the given options based on our derivation:

  • Option 1: \( \rm g_m=g_{mo}\left[ 1- \left(\frac{V_{GS}}{V_P}\right) \right]^{\frac{3}{2 }}\)
    This expression is incorrect. The power in the term \( \left[ 1- \left(\frac{V_{GS}}{V_P}\right) \right] \) should be 1, not 3/2.
  • Option 2: \( \rm g_m=g_{mo}\left[ 1- \left(\frac{V_{GS}}{V_P}\right) \right]\)
    This matches our derived formula. It accurately represents the transconductance of a JFET as a function of VGS.
  • Option 3: \( \rm g_m=g_{mo}\left[ 1-\frac{V_{GS}}{V_P} \right]^2\)
    This expression is incorrect. The term \( \left[ 1-\frac{V_{GS}}{V_P} \right]^2 \) is part of the Shockley equation for drain current (ID), not transconductance (gm).
  • Option 4: \( \rm g_m=g_{mo}\sqrt{ 1- \left(\frac{V_{GS}}{V_P}\right) } \)
    This expression is incorrect. The power in the term \( \left[ 1- \left(\frac{V_{GS}}{V_P}\right) \right] \) should be 1, not 1/2 (square root).

Therefore, the correct expression for the transconductance (gm) of a JFET is \( \rm g_m=g_{mo}\left[ 1- \left(\frac{V_{GS}}{V_P}\right) \right]\). This formula is crucial for analyzing and designing JFET amplifier circuits, as it directly relates to the voltage gain characteristics of the device.

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Important Questions from Field Effect Transistors

  1. Which of the following is the characteristic of Field-effect transistor?

  2. In junction field effect transistor, the drain current can be approximated as:
  3. Field Effect transistor is:

  4. A FET has

  5. The main drawback of a JFET is its

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