The exact relationship between modulus of rigidity C, modulus of elasticity E and Poisson’s ratio ν is expressed as
C = \(\rm {E \over 2(1+v)}\)
In mechanics of materials, we study how solid bodies deform under stress. Elastic constants are properties of a material that describe its stiffness or resistance to deformation under applied forces in the elastic range. These constants relate stress and strain. The question asks about the relationship between three fundamental elastic constants: Modulus of Rigidity, Modulus of Elasticity, and Poisson's ratio.
These elastic constants are not independent of each other. For isotropic materials (materials whose properties are the same in all directions), there are specific relationships that connect E, C, \(\nu\), and the Bulk Modulus (K). The question focuses on the relationship between E, C, and \(\nu\).
The widely accepted and experimentally verified relationship between Modulus of Elasticity (E), Modulus of Rigidity (C), and Poisson's ratio (\(\nu\)) for an isotropic material is given by the formula:
\[ E = 2C(1 + \nu) \]
This formula directly relates the three constants mentioned in the question.
The options provided express C in terms of E and \(\nu\). We can rearrange the formula \(E = 2C(1 + \nu)\) to solve for C:
Divide both sides by \(2(1 + \nu)\):
\[ C = \frac{E}{2(1 + \nu)} \]
Now let's compare this derived expression with the given options:
Therefore, the exact relationship expressing Modulus of Rigidity (C) in terms of Modulus of Elasticity (E) and Poisson's ratio (\(\nu\)) is \(C = \frac{E}{2(1+v)}\).
| Constants Related | Relationship Formula |
|---|---|
| E, C, \(\nu\) | \(E = 2C(1 + \nu)\) or \(C = \frac{E}{2(1 + \nu)}\) |
| E, K, \(\nu\) | \(E = 3K(1 - 2\nu)\) or \(K = \frac{E}{3(1 - 2\nu)}\) |
| E, C, K | \(E = \frac{9KC}{3K + C}\) |
| Constant | Symbol | Relationship |
|---|---|---|
| Modulus of Elasticity | E | \(E = 2C(1 + \nu) = 3K(1 - 2\nu) = \frac{9KC}{3K + C}\) |
| Modulus of Rigidity | C (or G) | \(C = \frac{E}{2(1 + \nu)}\) |
| Bulk Modulus | K | \(K = \frac{E}{3(1 - 2\nu)}\) |
| Poisson's Ratio | \(\nu\) | \(\nu = \frac{3K - 2C}{6K + 2C}\) |
Besides E, C, and \(\nu\), the Bulk Modulus (K) is another important elastic constant. It measures a material's resistance to uniform compression or volume change. It is defined as the ratio of volumetric stress to volumetric strain.
For any isotropic elastic material, only two of the four elastic constants (E, C, K, \(\nu\)) are independent. If you know any two, you can determine the other two using the relationships summarized in the tables above.
It's important to note that these relationships apply specifically to isotropic materials that follow Hooke's Law (linear elastic behavior). Anisotropic materials, like wood or composite materials, have properties that vary with direction, and their stress-strain relationships are more complex, requiring more than two independent elastic constants to describe their behavior.
The bulk modulus of elasticity
The modulus of elasticity of steel is assumed to be:
What is Bulk Modulus?
The shear modulus (G), modulus of elasticity (E) and the Poisson's ratio (μ) of a material are related as:
Young’s modulus, Bulk modulus (K) and shear modulus (G) are related by