Question
The equation of the normal to the curve \(y = 4x^3 + 2 \sin(x)\) at \((0, 3)\) \(y = 4x^3 + 2 \sin(x)\) at \( (0, 3) \)
The correct answer is
x+ 2y=6
Given curve is
\( y = 4x^3 + 2 \sin(x) \) at \( (0, 3) \)\( \frac{dy}{dx} = 12x^2 + 2 \cos(x) \)
Slope tangent at \( (0, 3) \) is 2
So, slope of normal is \( -\frac{1}{2} \)
Equation of normal is
\( y - 3 = -\frac{1}{2}(x - 0) \)\( 2y - 6 = -x \)
\( x + 2y = 6 \)
Was this answer helpful?
Important Questions from Mixed Topics (CUET-UG)
Which of the following statement is incorrect?
Which of the following statement is TRUE?
Which of the following statement is correct?
Match List-I with List-II:
List-I List-II (A) Primary Market (I) Stock Exchange (B) Secondary Market (II) Treasury Bill (C) Maturity Period of 15 days to one year (III) New Issue Market (D) Available for minimum amount of ₹25000 (IV) Commercial paper
Need Expert Advice?
