The energy of a hydrogen molecule in its ground state equilibrium configuration is $-31.7\ eV$.Its dissociation energy is_______________$\ eV$. (Up to one decimal place)
Understanding Molecular Dissociation Energy
The dissociation energy is the minimum energy required to break apart a molecule into its constituent atoms starting from its ground state. For a diatomic molecule like hydrogen (H2), it's the energy needed to convert H2 into two separate H atoms.
Given Hydrogen Molecule Energy
The energy of the hydrogen molecule (H2) in its ground state equilibrium configuration is given as $E_{\text{molecule}} = -31.7\ eV$. This energy value represents the molecule's stability relative to two free hydrogen atoms.
The energy of a single hydrogen atom (H) in its ground state is a known fundamental constant: $E_{\text{H}} = -13.6\ eV$.
Calculating H2 Dissociation Energy
First, calculate the total energy of two separated hydrogen atoms:
$ E_{\text{atoms}} = 2 \times E_{\text{H}} = 2 \times (-13.6\ eV) = -27.2\ eV $
The dissociation energy ($D_0$) is the difference between the energy of the separated atoms and the energy of the molecule:
$ D_0 = E_{\text{atoms}} - E_{\text{molecule}} $
Substitute the known values:
$ D_0 = (-27.2\ eV) - (-31.7\ eV) $
$ D_0 = -27.2\ eV + 31.7\ eV $
$ D_0 = 4.5\ eV $
Result Confirmation
The calculated dissociation energy for the hydrogen molecule is $4.5\ eV$. This value falls within the provided range of 4.4 eV to 4.6 eV.
Important Questions from Chemical Bonding
The element having which of the following electronic configuration will have highest ionization energy?
Which of the following is true about interhalogen compounds?
The shape of the molecule depends on the _______
In Co-ordinate bond, the acceptor atoms must essentially contain in its valency shell an orbital:
The geometrical shape of PCl5 molecules is
