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Question

The eigen value corresponding to the eigen vector $\begin{bmatrix} 1 \\ 1 \end{bmatrix}$ for the matrix $\begin{bmatrix} 4 & 2 \\ 2 & 4 \end{bmatrix}$ , is

The correct answer is
6

Finding the Eigenvalue for a Given Matrix and Eigenvector

The question asks for the eigenvalue corresponding to a specific eigenvector for a given matrix. We are provided with the matrix $A = \begin{bmatrix} 4 & 2 \\ 2 & 4 \end{bmatrix}$ and the eigenvector $v = \begin{bmatrix} 1 \\ 1 \end{bmatrix}$.

Understanding Eigenvalues and Eigenvectors

An eigenvalue ($\lambda$) and its corresponding non-zero eigenvector ($v$) of a square matrix ($A$) satisfy the equation:

$Av = \lambda v$

This equation means that when the matrix $A$ acts on the eigenvector $v$, the result is simply the eigenvector scaled by a factor $\lambda$. This scaling factor $\lambda$ is the eigenvalue.

Step-by-Step Calculation

To find the eigenvalue $\lambda$, we need to compute the product of the matrix $A$ and the eigenvector $v$, and then equate it to $\lambda v$.

Step 1: Calculate the Matrix-Vector Product ($Av$)

We multiply the given matrix $A$ by the given eigenvector $v$:

$Av = \begin{bmatrix} 4 & 2 \\ 2 & 4 \end{bmatrix} \begin{bmatrix} 1 \\ 1 \end{bmatrix}$

Performing the matrix multiplication:

$ Av = \begin{bmatrix} (4 \times 1) + (2 \times 1) \\ (2 \times 1) + (4 \times 1) \end{bmatrix} $ $ Av = \begin{bmatrix} 4 + 2 \\ 2 + 4 \end{bmatrix} $ $ Av = \begin{bmatrix} 6 \\ 6 \end{bmatrix} $

Step 2: Relate the Result to $\lambda v$

Now, we use the eigenvalue equation $Av = \lambda v$:

$ \begin{bmatrix} 6 \\ 6 \end{bmatrix} = \lambda \begin{bmatrix} 1 \\ 1 \end{bmatrix} $

Distributing the scalar $\lambda$ on the right side:

$ \begin{bmatrix} 6 \\ 6 \end{bmatrix} = \begin{bmatrix} \lambda \times 1 \\ \lambda \times 1 \end{bmatrix} $ $ \begin{bmatrix} 6 \\ 6 \end{bmatrix} = \begin{bmatrix} \lambda \\ \lambda \end{bmatrix} $

Step 3: Determine the Eigenvalue ($\lambda$)

By comparing the corresponding elements of the resulting vectors, we can determine the value of $\lambda$:

  • From the first element: $6 = \lambda$
  • From the second element: $6 = \lambda$

Both comparisons yield the same value for $\lambda$.

Therefore, the eigenvalue corresponding to the eigenvector $\begin{bmatrix} 1 \\ 1 \end{bmatrix}$ for the matrix $\begin{bmatrix} 4 & 2 \\ 2 & 4 \end{bmatrix}$ is 6.

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Important Questions from Mixed Topic (CUET PG)

  1. Who was the founder of Bolshevik Communist party?
  2. What is the key guide to statecraft in the realist tradition?
  3. Chronologically arrange the events in the Cold War period.
    A. Berlin Wall is constructed
    B. Communist China joins the UN
    C. Soviet invasion of Czechoslovakia
    D. Berlin Blockade
    Choose the correct answer from the options given below:
  4. Morgenthau's principles of political realism are:
    A. Politics is rooted in permanent and unchanging human nature which is basically self centred, self-regarding and self-interested
    B. Politics is an autonomous sphere of action and cannot therefore be reduced to morals
    C. International Politics is an arena of conflicting self-interests
    D. The ethics of international relations is situational ethics which is very different from private morality
    Choose the correct answer from the options given below:

  5. Who among the following political thinkers consider the anarchical self help system to be a compelling factor for States to maximise their relative power positions?

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