All Exams Test series for 1 year @ ₹349 only
Question

The efficiency of rectification of a full wave rectifier is:

The correct answer is η = 8/π 2

Efficiency of a Full Wave Rectifier

A rectifier is an electronic circuit that converts alternating current (AC) to direct current (DC). There are mainly two types: half-wave rectifiers and full-wave rectifiers. A full-wave rectifier utilizes both positive and negative half-cycles of the AC input to produce a DC output, leading to higher efficiency compared to a half-wave rectifier.

The efficiency ($\eta$) of a rectifier is a measure of how effectively it converts AC power into DC power. It is defined as the ratio of the DC output power ($P_{dc}$) delivered to the load to the total AC input power ($P_{ac}$) supplied to the rectifier circuit, usually expressed as a percentage:

$\eta = \frac{P_{dc}}{P_{ac}} \times 100\%$

For a full wave rectifier, the theoretical maximum efficiency is calculated based on the ideal conversion. The standard formula derived for the efficiency of a full wave rectifier is:

$\eta = \frac{8}{\pi^2}$

This formula represents the maximum possible efficiency. When calculated numerically, this value is approximately:

$\eta = \frac{8}{(3.14159)^2} \approx \frac{8}{9.8696} \approx 0.8106$

In percentage, the maximum efficiency of a full wave rectifier is about $0.8106 \times 100\% = 81.06\%$. Often, this is stated as 81.2% due to approximations in calculation methods, but the exact formula remains $8/\pi^2$.

Let's look at the given options:

  • Option 1: $\eta = 8/\pi$. This is incorrect.
  • Option 2: $\eta = 8/\pi^2$. This matches the standard formula for the efficiency of a full wave rectifier.
  • Option 3: $\eta = 4/\pi^2$. This is incorrect; $4/\pi^2$ is related to the efficiency of a half-wave rectifier.
  • Option 4: $\eta = 4/\pi$. This is incorrect.

Therefore, the correct formula for the efficiency of a full wave rectifier is $8/\pi^2$.

Was this answer helpful?

Important Questions from Rectifier Circuits

  1. What is the ripple factor of full-wave bridge rectifier?

  2. The maximum efficiency of a half-wave rectifier is

  3. For a full wave rectifier, the output frequency

  4. A full wave rectifier is supplied from a $20$ V AC supply. Average output voltage is:
  5. A half wave rectifier requires -

Need Expert Advice?

Start Your Preparation with Prepp Mobile App

Download the app from Google Play & App Store
Download the app from Google Play & App Store
Prepp Mobile App