The efficiency of a sedimentation tank (in percentage) is calculated using which of the following formulas?
Sedimentation tanks, also known as clarifiers, are crucial components in wastewater treatment plants. Their primary function is to remove suspended solids from water or wastewater through the process of sedimentation, where gravity causes the particles to settle out of the liquid.
The efficiency of a sedimentation tank indicates how effectively it removes these suspended particles. This efficiency is largely dependent on two key parameters:
The efficiency of a sedimentation tank for removing particles with a specific settling velocity is determined by comparing the settling velocity of the particle to the overflow velocity of the tank. The formula represents the fraction of particles with settling velocity \(v_s\) that will be removed in a tank with overflow velocity \(v_o\).
The formula for calculating the efficiency (in percentage) for removing particles with a settling velocity \(v_s\) in a sedimentation tank with an overflow velocity \(v_o\) is given by:
$$\text{Efficiency} = \left(\frac{v_s}{v_o}\right) \times 100$$
This formula assumes that all particles with \(v_s \ge v_o\) are removed, and for particles with \(v_s < v_o\), the fraction removed is \(v_s/v_o\). The overall efficiency for a mixture of particles is a more complex calculation involving the particle size distribution, but for a single settling velocity or as a general indicator related to the 'critical' settling velocity equal to the overflow rate, this ratio is fundamental.
Let's look at the provided options and compare them to the correct formula:
Based on the standard principles of sedimentation tank design and performance, the efficiency calculation involves the ratio of settling velocity to overflow velocity.
Therefore, the correct formula for calculating the efficiency of a sedimentation tank (related to particles with settling velocity \(v_s\) in a tank with overflow velocity \(v_o\)) is \( (v_s / v_o) \times 100 \).
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