The distance between the points (2, 3) and (4, 1) is.
2√2
Using the distance formula:
Distance = √[(x₂ − x₁)² + (y₂ − y₁)²]
For the points (2, 3) and (4, 1):
= √[(4 − 2)² + (1 − 3)²]
= √[2² + (−2)²]
= √(4 + 4)
= √8
= 2√2
Final Answer: 2√2
Important Questions from Distance between points
Determine the shortest distance between the lines l1 and l2 whose vector equations are
\(\vec{r}=2 \hat{\imath}+\hat{\jmath}+\lambda(2 \hat{\imath}-\hat{\jmath}+\hat{k}) \quad \ldots(1)\)
\(\vec{r}=3 \hat{\imath}+\hat{\jmath}-\hat{k}+\mu(3 \hat{\imath}-5 \hat{\jmath}+2 \hat{k}) \quad \ldots(2)\)
Find the distance between the points P (2, -1, 3) and Q (-5, 2, 1)?
The sum of distances from origin to (0, 5, 5) and (5, 8, 6) is:
The vertices of a triangle are \(A(2, 0, 0)\), \(B(0, 6, 0)\) and \(C(0, 0, 4)\). If \(AD\), \(BE\) and \(CF\) are the medians of the triangle, then what is \(AD^2 + BE^2 + CF^2\) equal to?
The distance of a point from the x-axis is called that point.
