(Given: $E=h\nu$ where $E$ is energy and $\nu$ is frequency.)
The question asks us to identify which pair of physical quantities has the same dimensions as Planck's constant ($h$). We are given a key formula relating energy ($E$), Planck's constant ($h$), and frequency ($\nu$): $E=h\nu$. This formula will be crucial for our dimensional analysis.
First, let's find the dimensional formula for Planck's constant ($h$) using the provided equation $E = h\nu$. We can rearrange this to solve for $h$:
$h = \frac{E}{\nu}$
To proceed, we need the dimensions of Energy ($E$) and frequency ($\nu$).
Now, we substitute these dimensions back into the equation for $h$:
$[h] = \frac{[E]}{[\nu]} = \frac{ML^2T^{-2}}{T^{-1}}
Simplifying this expression gives us the dimensions of Planck's constant:
$[h] = ML^{2}T^{-2 - (-1)} = ML^{2}T^{-1}
Our goal is to find which of the given options results in these dimensions: $ML^2T^{-1}$.
Let's calculate the dimensions for each combination given in the options:
| Option Description | Calculation of Dimensions | Resulting Dimensions | Matches $[h]$? |
|---|---|---|---|
| 1. Energy $\times$ frequency | We know $[E] = ML^2T^{-2}$ and $[\nu] = T^{-1}$. Dimensions = $[E] \times [\nu] = (ML^2T^{-2}) \times (T^{-1})$ | $ML^2T^{-3}$ | No |
| 2. Momentum $\times$ velocity | The dimensions of Momentum are $[p] = MLT^{-1}$ (Mass $\times$ Velocity). The dimensions of Velocity are $[v] = LT^{-1}$. Dimensions = $[p] \times [v] = (MLT^{-1}) \times (LT^{-1})$ | $ML^2T^{-2}$ | No |
| 3. Force $\times$ time | The dimensions of Force are $[F] = MLT^{-2}$. The dimensions of time are $[t] = T$. Dimensions = $[F] \times [t] = (MLT^{-2}) \times T$ | $MLT^{-1}$ | No |
| 4. Energy $\times$ time | We know $[E] = ML^2T^{-2}$. The dimensions of time are $[t] = T$. Dimensions = $[E] \times [t] = (ML^2T^{-2}) \times T$ | $ML^2T^{-1}$ | Yes |
After evaluating each option:
Comparing these results with the dimensions of Planck's constant ($[h] = ML^2T^{-1}$), we find that only Option 4 matches.
Therefore, the combination of Energy $\times$ time has the same dimensions as Planck's constant ($h$). These dimensions are also known as action or angular momentum.
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