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Question

Which of the following combinations of physical quantities has the same dimensions as Planck's constant ($h$)?
(Given: $E=h\nu$ where $E$ is energy and $\nu$ is frequency.)

The correct answer is
Energy $\times$ time

Planck's Constant Dimensions Explained

The question asks us to identify which pair of physical quantities has the same dimensions as Planck's constant ($h$). We are given a key formula relating energy ($E$), Planck's constant ($h$), and frequency ($\nu$): $E=h\nu$. This formula will be crucial for our dimensional analysis.

Deriving Dimensions of Planck's Constant

First, let's find the dimensional formula for Planck's constant ($h$) using the provided equation $E = h\nu$. We can rearrange this to solve for $h$:

$h = \frac{E}{\nu}$

To proceed, we need the dimensions of Energy ($E$) and frequency ($\nu$).

  • Energy ($E$): Energy has the same dimensions as work done. Work is defined as Force $\times$ Distance. The dimensions of Force are $MLT^{-2}$ (Mass $\times$ Acceleration), and the dimensions of Distance are $L$. Therefore, the dimensions of Energy are: $[E] = [Force] \times [Distance] = (MLT^{-2}) \times L = ML^2T^{-2}$
  • Frequency ($\nu$): Frequency represents cycles per unit time. Its dimensions are: $[\nu] = T^{-1}$

Now, we substitute these dimensions back into the equation for $h$:

$[h] = \frac{[E]}{[\nu]} = \frac{ML^2T^{-2}}{T^{-1}}

Simplifying this expression gives us the dimensions of Planck's constant:

$[h] = ML^{2}T^{-2 - (-1)} = ML^{2}T^{-1}

Our goal is to find which of the given options results in these dimensions: $ML^2T^{-1}$.

Analyzing Options for Physical Quantity Dimensions

Let's calculate the dimensions for each combination given in the options:

Option Description Calculation of Dimensions Resulting Dimensions Matches $[h]$?
1. Energy $\times$ frequency We know $[E] = ML^2T^{-2}$ and $[\nu] = T^{-1}$. Dimensions = $[E] \times [\nu] = (ML^2T^{-2}) \times (T^{-1})$ $ML^2T^{-3}$ No
2. Momentum $\times$ velocity The dimensions of Momentum are $[p] = MLT^{-1}$ (Mass $\times$ Velocity). The dimensions of Velocity are $[v] = LT^{-1}$. Dimensions = $[p] \times [v] = (MLT^{-1}) \times (LT^{-1})$ $ML^2T^{-2}$ No
3. Force $\times$ time The dimensions of Force are $[F] = MLT^{-2}$. The dimensions of time are $[t] = T$. Dimensions = $[F] \times [t] = (MLT^{-2}) \times T$ $MLT^{-1}$ No
4. Energy $\times$ time We know $[E] = ML^2T^{-2}$. The dimensions of time are $[t] = T$. Dimensions = $[E] \times [t] = (ML^2T^{-2}) \times T$ $ML^2T^{-1}$ Yes

Identifying Correct Dimension Match

After evaluating each option:

  • Option 1 (Energy $\times$ frequency) yields dimensions of $ML^2T^{-3}$.
  • Option 2 (Momentum $\times$ velocity) yields dimensions of $ML^2T^{-2}$.
  • Option 3 (Force $\times$ time) yields dimensions of $MLT^{-1}$.
  • Option 4 (Energy $\times$ time) yields dimensions of $ML^2T^{-1}$.

Comparing these results with the dimensions of Planck's constant ($[h] = ML^2T^{-1}$), we find that only Option 4 matches.

Therefore, the combination of Energy $\times$ time has the same dimensions as Planck's constant ($h$). These dimensions are also known as action or angular momentum.

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Important Questions from Units, Dimensions and Measurements

  1. Which one of the following is the usual unit of measurement for Air Pressure used in India?

  2. Which one of the following physical quantity has the same unit as that of pressure

  3. The SI unit of acceleration is

  4. Light year is a unit for measurement of

  5. A light year is a unit of measurement of

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