The difference, the sum and the product of two integers are in the proportion 1 ∶ 3 ∶ 10. The two integers are:
Let the two integers be $x$ and $y$. We are given that the difference, the sum, and the product of these two integers are in the proportion $1 : 3 : 10$. Without loss of generality, let's assume $x \ge y$ so the difference is non-negative.
According to the problem statement, we have the following relationships:
The ratio is given as $(x-y) : (x+y) : (xy) = 1 : 3 : 10$. This implies that there exists a constant $k$ such that:
$\frac{x-y}{1} = \frac{x+y}{3} = \frac{xy}{10} = k$
From the ratio relationship, we can write a system of three equations:
We need to find the values of $x$ and $y$ that satisfy these equations.
Let's solve the first two equations for $x$ and $y$ in terms of $k$.
Add equation (1) and equation (2):
$(x - y) + (x + y) = k + 3k$
$2x = 4k$
$x = 2k$
Subtract equation (1) from equation (2):
$(x + y) - (x - y) = 3k - k$
$2y = 2k$
$y = k$
Now we have $x = 2k$ and $y = k$. Since we assumed $x \ge y$, this is consistent as long as $k \ge 0$.
Substitute the expressions for $x$ and $y$ into equation (3):
$xy = 10k$
$(2k)(k) = 10k$
$2k^2 = 10k$
Rearrange the equation to solve for $k$:
$2k^2 - 10k = 0$
$2k(k - 5) = 0$
This equation gives two possible values for $k$:
Let's consider the two cases for $k$:
Case 1: $k = 0$
If $k = 0$, then $x = 2(0) = 0$ and $y = 0$.
Difference: $0 - 0 = 0$
Sum: $0 + 0 = 0$
Product: $0 \times 0 = 0$
The ratio is $0 : 0 : 0$. This is not in the proportion $1 : 3 : 10$, so $k=0$ is not a valid solution for this problem.
Case 2: $k = 5$
If $k = 5$, then $x = 2(5) = 10$ and $y = 5$.
The two integers are 10 and 5.
Let's check if the integers 10 and 5 satisfy the given ratio:
The ratio of difference : sum : product is $5 : 15 : 50$.
To simplify this ratio, we can divide all terms by the greatest common divisor, which is 5:
$\frac{5}{5} : \frac{15}{5} : \frac{50}{5} = 1 : 3 : 10$
This matches the ratio given in the problem. Therefore, the two integers are 10 and 5.
The problem asks for the two integers. We found the integers are 5 and 10. Let's look at the given options:
| Option | Integers | Difference | Sum | Product | Ratio (Difference:Sum:Product) |
|---|---|---|---|---|---|
| 1 | 3, 9 | $9-3=6$ | $9+3=12$ | $3 \times 9=27$ | $6:12:27 = 2:4:9$ (Not 1:3:10) |
| 2 | 2, 5 | $5-2=3$ | $5+2=7$ | $2 \times 5=10$ | $3:7:10$ (Not 1:3:10) |
| 3 | 5, 10 | $10-5=5$ | $10+5=15$ | $5 \times 10=50$ | $5:15:50 = 1:3:10$ (Matches) |
| 4 | 3, 10 | $10-3=7$ | $10+3=13$ | $3 \times 10=30$ | $7:13:30$ (Not 1:3:10) |
The pair of integers (5, 10) is the one that satisfies the given condition that their difference, sum, and product are in the proportion 1 : 3 : 10.
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2 The product of three consecutive natural numbers can be equal to their sum.
Which of the above statements is/are correct ?
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2. The difference between the two digits of the number can be determined.
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