The difference, the sum and the product of two integers are in the proportion 1 ∶ 3 ∶ 10. The two integers are:
Let the two integers be $x$ and $y$. We are given that the difference, the sum, and the product of these two integers are in the proportion $1 : 3 : 10$. Let's assume, without loss of generality, that $x \ge y$. The difference is $x - y$, the sum is $x + y$, and the product is $x \times y$.
We can represent the given proportion using a constant $k$. This means:
We now have a system of three equations. We can solve the first two equations simultaneously to find $x$ and $y$ in terms of $k$.
Add Equation 1 and Equation 2:
$(x - y) + (x + y) = k + 3k$
$2x = 4k$
$x = \frac{4k}{2}$
$x = 2k$
Now substitute the value of $x$ into Equation 2:
$(2k) + y = 3k$
$y = 3k - 2k$
$y = k$
Now substitute the expressions for $x$ and $y$ in terms of $k$ into Equation 3:
$x \times y = 10k$
$(2k) \times (k) = 10k$
$2k^2 = 10k$
To solve for $k$, rearrange the equation:
$2k^2 - 10k = 0$
Factor out $2k$:
$2k(k - 5) = 0$
This gives two possible solutions for $k$:
If $k = 0$, then $x = 2(0) = 0$ and $y = 0$. The difference, sum, and product would all be 0, and the ratio $0:0:0$ is undefined, so $k=0$ is not a valid solution.
If $k = 5$, this is a valid solution.
Using $k = 5$, we can find the values of $x$ and $y$:
$x = 2k = 2(5) = 10$
$y = k = 5$
So, the two integers are 10 and 5.
Let's check if the difference, sum, and product of 10 and 5 are in the ratio $1 : 3 : 10$.
The ratio of the difference, sum, and product is $5 : 15 : 50$.
Dividing all parts of the ratio by 5, we get:
$\frac{5}{5} : \frac{15}{5} : \frac{50}{5} = 1 : 3 : 10$
This matches the given proportion.
Thus, the two integers are 5 and 10.
Read the given figure and find the region representing persons who are educated and employed but not confirmed in job.

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