The dielectric constant of a vacuum is _____.
Exactly 1
The question asks about the value of the dielectric constant for a vacuum. The dielectric constant, also known as relative permittivity, is a property of a material that describes how it responds to an applied electric field. It essentially measures the ability of an insulating material to store electrical energy in the form of an electric field.
Mathematically, the dielectric constant (often represented as $\kappa$ or $\epsilon_r$) of a medium is defined as the ratio of the permittivity of that medium ($\epsilon$) to the permittivity of free space (vacuum, $\epsilon_0$):
$$ \epsilon_r = \frac{\epsilon}{\epsilon_0} $$
Here:
The dielectric constant indicates how much the electric field is reduced inside the material compared to a vacuum when the same external field is applied. Materials with higher dielectric constants are better at reducing the electric field.
By definition, the vacuum serves as the baseline or reference medium for measuring dielectric properties. The permittivity of a vacuum is denoted as $\epsilon_0$. When we calculate the dielectric constant for a vacuum itself using the formula:
$$ \epsilon_r (\text{vacuum}) = \frac{\epsilon_0}{\epsilon_0} $$
This simplifies to:
$$ \epsilon_r (\text{vacuum}) = 1 $$
Therefore, the dielectric constant of a vacuum is exactly 1.
Based on the definition and the fundamental constants involved, the dielectric constant of a vacuum is precisely 1.
Electric potential $V$, is a ____ field, and electric field intensity $E$, is a ______ field.
According to Gauss’s Law, the surface integral of the normal component of electric flux density D over a closed surface containing charge Q is:
The electric potential at the surface of an atomic nucleus (z = 50) of radius 9 × 10-15 m is ______________.
What is the relative permittivity of slate dielectric?