The curved surface area of a cylinder is 968 cm2. If the height of the cylinder is 11 cm, then what will be the diameter of its base?
28 cm
Let's solve this geometry problem involving the curved surface area of a cylinder. We are given the curved surface area and the height of the cylinder, and we need to find the diameter of its base.
The curved surface area (CSA) of a cylinder is the area of the lateral surface, excluding the top and bottom circular bases. It can be visualized as the area of a rectangle formed when the cylinder's curved surface is unrolled. The length of this rectangle is the circumference of the base ($2\pi r$), and the width is the height of the cylinder ($h$).
The formula for the curved surface area of a cylinder is:
$\text{CSA} = 2 \pi r h$
where:
We are given the following values:
We need to find the diameter (d) of the base. Remember that the diameter is twice the radius ($d = 2r$).
We can use the CSA formula and plug in the given values to find the radius $r$. We'll use $\pi = 22/7$ for this calculation.
$\text{CSA} = 2 \pi r h$
Substitute the known values:
$968 = 2 \times \frac{22}{7} \times r \times 11$
Now, let's simplify the right side of the equation:
$968 = \frac{44}{7} \times r \times 11$
$968 = \frac{484}{7} \times r$
To find $r$, we need to isolate it. Multiply both sides by 7/484:
$r = 968 \times \frac{7}{484}$
We can simplify 968/484. Notice that $484 \times 2 = 968$.
$r = 2 \times 7$
$r = 14$
So, the radius of the base is 14 cm.
The diameter $d$ is twice the radius $r$.
$d = 2r$
Substitute the calculated radius:
$d = 2 \times 14$
$d = 28$
The diameter of the base of the cylinder is 28 cm.
Given the curved surface area of 968 cm$^2$ and a height of 11 cm, the diameter of the cylinder's base is 28 cm.
Here's a summary of the values:
| Property | Value | Unit |
|---|---|---|
| Curved Surface Area (CSA) | 968 | cm$^2$ |
| Height (h) | 11 | cm |
| Calculated Radius (r) | 14 | cm |
| Calculated Diameter (d) | 28 | cm |
Beyond the curved surface area, there are other important formulas related to cylinders:
$\text{TSA} = \text{CSA} + \text{Area of two bases}$
$\text{TSA} = 2 \pi r h + 2 \pi r^2$
$\text{TSA} = 2 \pi r (h + r)$
$\text{Volume} = (\text{Area of base}) \times h$
$\text{Volume} = \pi r^2 h$
Understanding these formulas helps in solving various problems related to cylinders.
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