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Question

The current population of a city is 11,02,500. If it has been increasing at the rate of 5% per annum, what was its population 2 years ago?

The correct answer is
10,00,000

Calculating Past City Population with Annual Growth

Problem Analysis

We are given the current population of a city and the annual growth rate. We need to find the population from 2 years ago.

  • Current Population ($P_{current}$) = 11,02,500
  • Annual Growth Rate ($R$) = 5%
  • Time Period ($T$) = 2 years
  • We need to find the Past Population ($P_{past}$).

Population Calculation Formula

The formula relating current population to past population with a constant annual growth rate is:

$P_{current} = P_{past} \times (1 + \frac{R}{100})^T$

To find the past population, we rearrange the formula:

$P_{past} = \frac{P_{current}}{(1 + \frac{R}{100})^T}$

Step-by-Step Solution

  1. Substitute the values into the formula:
    $P_{past} = \frac{11,02,500}{(1 + \frac{5}{100})^2}$
  2. Calculate the term inside the parenthesis:
    $1 + \frac{5}{100} = 1 + 0.05 = 1.05$
  3. Calculate the denominator (growth factor raised to the power of time):
    $(1.05)^2 = 1.1025$
  4. Divide the current population by the calculated factor:
    $P_{past} = \frac{11,02,500}{1.1025}$
  5. Final Calculation:
    $P_{past} = 10,00,000$

Conclusion

The population of the city 2 years ago was 10,00,000.

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