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Question

The critical angle for diamond is approximately ________.

The correct answer is
$24.4^{\circ}$

Understanding the Critical Angle for Diamond

The question asks for the specific value of the critical angle for diamond. The critical angle is a concept in optics related to total internal reflection.

What is the Critical Angle?

The critical angle ($\theta_c$) occurs at the boundary between two different transparent media. It is defined as the angle of incidence ($\theta_i$) in the optically denser medium for which the angle of refraction ($\theta_r$) in the optically rarer medium is exactly $90^{\circ}$.

Formula for Critical Angle

The relationship between the critical angle and the refractive indices of the two media is given by Snell's Law. When light travels from a denser medium (with refractive index $n_1$) to a rarer medium (with refractive index $n_2$), the critical angle is calculated using the formula:

$ \sin(\theta_c) = \frac{n_2}{n_1} $

In the case of light going from diamond to air, $n_1$ is the refractive index of diamond, and $n_2$ is the refractive index of air ($n_{air} \approx 1$). So the formula simplifies to:

$ \sin(\theta_c) = \frac{1}{n_{diamond}} $

Calculating the Critical Angle for Diamond

Diamond is known for its high refractive index, which contributes to its sparkle and brilliance through total internal reflection. The refractive index ($n$) of diamond is approximately $2.42$.

Using the formula:

  1. Substitute the refractive index of diamond into the formula:

    $ \sin(\theta_c) = \frac{1}{2.42} $

  2. Calculate the value of $\frac{1}{2.42}$:

    $ \frac{1}{2.42} \approx 0.4132 $

  3. Find the angle ($\theta_c$) by taking the inverse sine (arcsin) of this value:

    $ \theta_c = \arcsin(0.4132) $

  4. Calculating this value gives the critical angle in degrees:

    $ \theta_c \approx 24.4^{\circ} $

Conclusion

Therefore, the critical angle for diamond is approximately $24.4^{\circ}$. This small critical angle means that light entering a diamond is very likely to undergo total internal reflection, bouncing around inside the gem and emerging from the top facets, creating its characteristic sparkle.

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Important Questions from Optics

  1. The line joining the centre of curvature and the pole of a given spherical mirror is called __________.
  2. What is the condition for total internal reflection to occur?
  3. Which type of lens is used in a simple microscope?
  4. A student shows a concave lens forming a diminished real image on the screen. The mistake is:
  5. The phenomenon of dispersion of light was first explained by ________.
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