The cost of 7 pens and 13 pencils is ₹128. If the cost of a pen decreases by ₹7 and the cost of a pencil increases by ₹2, then the cost of 14 pens and 10 pencils is ₹98. What is the original cost of 9 pens and 7 pencils?
This problem involves finding the original costs of pens and pencils given two different scenarios involving their prices and total costs. We can solve this using a system of linear equations.
First, let's define the variables:
Now, let's translate the information given in the problem into equations:
Scenario 1: The cost of 7 pens and 13 pencils is ₹128.
This gives us our first equation:
$7p + 13c = 128$
Scenario 2: The cost of a pen decreases by ₹7, and the cost of a pencil increases by ₹2. The new cost of 14 pens and 10 pencils is ₹98.
The new cost of a pen is \( p - 7 \).
The new cost of a pencil is \( c + 2 \).
The equation for this scenario is:
$14(p - 7) + 10(c + 2) = 98$
Let's simplify the second equation:
$14p - 98 + 10c + 20 = 98$
$14p + 10c - 78 = 98$
$14p + 10c = 98 + 78$
$14p + 10c = 176$
We can simplify this further by dividing the entire equation by 2:
$7p + 5c = 88$
Now we have a system of two linear equations:
| Equation 1: | $7p + 13c = 128$ |
| Equation 2: | $7p + 5c = 88$ |
We can solve this system using the elimination method. Notice that the coefficient of \( p \) is the same (7) in both equations. Let's subtract Equation 2 from Equation 1:
$(7p + 13c) - (7p + 5c) = 128 - 88$
$7p + 13c - 7p - 5c = 40$
$8c = 40$
Now, solve for \( c \):
$c = \frac{40}{8}$
$c = 5$
So, the original cost of a pencil is ₹5.
Next, substitute the value of \( c \) (which is 5) back into either Equation 1 or Equation 2 to find \( p \). Let's use the simplified Equation 2:
$7p + 5c = 88$
$7p + 5(5) = 88$
$7p + 25 = 88$
Subtract 25 from both sides:
$7p = 88 - 25$
$7p = 63$
Now, solve for \( p \):
$p = \frac{63}{7}$
$p = 9$
So, the original cost of a pen is ₹9.
The question asks for the original cost of 9 pens and 7 pencils.
We need to calculate: $9p + 7c$
Substitute the values we found for \( p \) and \( c \):
$9(9) + 7(5)$
$81 + 35$
$116$
Therefore, the original cost of 9 pens and 7 pencils is ₹116.
Six years ago, the ratio of ages of A to B was 7 ∶ 5. After 4 years from now, the ratio of their ages will be 11 ∶ 9. What is A’s age at present?
7p - [3q - {8p - (4q - 10p)}] = ?
Surya is 25 years older than his son. In 5 years, he will be twice as old as his son. What will be Surya’s age after 3 years?
The difference between the ages of two sisters is 2 years when father’s age is 52. Father is elder by 2 years to mother. Elder sister’s age is half of mother’s age. Find the age of younger sister?
The sum of the digits of a 2 digit number is 9, When 27 is added to the number, the digits get interchanged. Find the number.
A. 45
B. 36
C. 18
D. 27