The correct order of decreasing electron gain enthalpy with negative sign for chalcogens is - Identify
S > Se > Te > O
Electron gain enthalpy is the energy change that occurs when an electron is added to a neutral isolated gaseous atom to form a gaseous anion. It is represented by $\Delta_e H$. When energy is released during this process, the electron gain enthalpy has a negative value, indicating that the atom has an affinity for electrons and forms a relatively stable anion. The more negative the electron gain enthalpy, the greater the tendency of an atom to accept an electron.
The question asks for the decreasing order of electron gain enthalpy with a negative sign for chalcogens (Group 16 elements: Oxygen (O), Sulfur (S), Selenium (Se), Tellurium (Te)). This means we need to arrange them from the most negative value (most energy released) to the least negative value (least energy released or potentially energy absorbed).
Generally, as we move down a group in the periodic table, the electron gain enthalpy becomes less negative. This is because:
Based on this general trend, we would expect the electron gain enthalpy (with negative sign) to decrease in the order S > Se > Te.
However, there is an exception to the general trend for the first element of some groups, including Group 16 (Chalcogens). Oxygen (O), being the first element, is significantly smaller than Sulfur (S), Selenium (Se), and Tellurium (Te).
When an electron is added to a small atom like Oxygen, it enters the already compact 2p subshell. The existing electrons in this small volume experience significant electron-electron repulsion. This strong repulsion between the incoming electron and the electrons already present in the small atom counteracts the attraction from the nucleus.
As a result, the electron gain enthalpy of Oxygen is less negative than that of Sulfur, and in fact, it is less negative than Se and Te as well. Sulfur, being larger, accommodates the incoming electron in the 3p subshell with much less inter-electronic repulsion, making its electron gain enthalpy more negative than Oxygen's.
Considering the general trend and the anomaly of Oxygen:
Combining these observations, the decreasing order of electron gain enthalpy with a negative sign is S > Se > Te > O.
| Element | Symbol | Relative Electron Gain Enthalpy Magnitude (Negative Sign) |
|---|---|---|
| Sulfur | S | Most Negative |
| Selenium | Se | Less Negative than S |
| Tellurium | Te | Less Negative than Se |
| Oxygen | O | Least Negative |
| Chalcogen | Atomic Size | Inter-electronic Repulsion | Electron Gain Enthalpy ($\Delta_e H$) Trend |
|---|---|---|---|
| O | Smallest | High (in 2p) | Least Negative (Anomaly) |
| S | Larger than O | Lower than O (in 3p) | Most Negative |
| Se | Larger than S | Lower than S (in 4p) | Less Negative than S |
| Te | Largest among these | Lower than Se (in 5p) | Least Negative among S, Se, Te |
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