The correct group, period and block for element Hassium (Hs) is
(Given : atomic number of Hs = 108)
To determine the position of an element in the periodic table, specifically its group, period, and block, we need to understand its atomic number and electronic configuration. The element in question is Hassium (Hs), and its atomic number is given as 108.
The electronic configuration helps us locate the element. Hassium (Hs) has an atomic number ($Z$) of 108. We can determine its configuration by building upon the preceding noble gas, which is Radon (Rn), with an atomic number of 86.
The configuration starts as: $[Rn]$
We need to add the remaining electrons ($108 - 86 = 22$ electrons) following the order of filling orbitals for period 7 elements. The general filling order after Radon is $7s$, followed by $5f$ (Actinides), and then $6d$ (Transition Metals).
Therefore, the complete electronic configuration for Hassium (Hs) is: $[Rn] 5f^{14} 6d^6 7s^2$.
We can now use this electronic configuration to find the element's properties:
The period number corresponds to the highest principal quantum number ($n$) occupied by electrons. In the configuration $[Rn] 5f^{14} 6d^6 7s^2$, the highest principal quantum number is 7 (from the $7s^2$ subshell). Thus, Hassium (Hs) is in the 7th period.
The block is determined by the type of orbital that receives the last electron. Since the last electrons in Hs enter the $d$ subshell ($6d^6$), Hassium belongs to the d-block. Elements in the d-block are transition metals.
For d-block elements, the group number is calculated by summing the number of electrons in the outermost $s$ subshell and the penultimate ($n-1$) $d$ subshell.
Electrons in the outermost $s$ subshell ($7s$) = 2
Electrons in the penultimate $d$ subshell ($6d$) = 6
Group Number = (Electrons in $(n-1)d$ subshell) + (Electrons in $ns$ subshell)
Group Number = $6 + 2 = 8$.
Therefore, Hassium (Hs) is in the 8th group.
Based on the electronic configuration and the rules for determining position in the periodic table, Hassium (Hs) with atomic number 108 is located in the:
Consider the following statements regarding the modern periodic table :
1. Elements in group 16 are also known as chalcogens
2. Elements in groups 3-12 are known as $p$-block elements
3. The $f$-block elements are also known as inner transition elements
4. Elements of groups 13-18 are known as transition elements
5. Elements in group 2 are also known as alkaline earth metals
Which of the statements given above is/are correct?
Which of the following order(s) of ionic radii is/are correct?
1. $O^{2-} < S^{2-} < Se^{2-} < Te^{2-}$
2. $Ti^{2+} < Ti^{3+} < Ti^{4+}$
3. $O^{2-} < F^{-} < Na^{+} < Mg^{2+}$
Select the answer using the code given below :