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Question

The correct electronic configuration of central metal ion in ferrocene with z-axis passing through the centre of two $C_5H_5^-$ rings and the metal ion is

The correct answer is
$d_{xy}^2 = d_{x^2-y^2}^2 < d_{z^2}^2 < d_{xz}^0 = d_{yz}^0$

Ferrocene Metal Ion Identification

The central metal ion in ferrocene ($Fe(C_5H_5)_2$) is iron in the +2 oxidation state, denoted as $Fe^{2+}$.

Neutral iron ($Fe$) has the electronic configuration $[Ar] 3d^6 4s^2$. Consequently, the $Fe^{2+}$ ion has a $d^6$ electronic configuration, meaning it has 6 electrons in its 3d orbitals.

d-Orbital Splitting and Electron Filling

In the ferrocene molecule, the $d$-orbitals of the $Fe^{2+}$ ion experience splitting due to the surrounding cyclopentadienyl ($C_5H_5^-$) ligands. This splitting results in distinct energy levels for the $d$-orbitals.

A common energy ordering for the $d$-orbitals in ferrocene, considering its symmetry ($D_{5h}$) and the interaction with ligand orbitals, is as follows (from lowest to highest energy):

  • $e_{2g}$ orbitals ($d_{xy}$ and $d_{x^2-y^2}$)
  • $a_{1g}$ orbital ($d_{z^2}$)
  • $e_{1g}$ orbitals ($d_{xz}$ and $d_{yz}$)

According to the Aufbau principle and Hund's rule, the 6 $d$-electrons of $Fe^{2+}$ will occupy these energy levels starting from the lowest:

  1. The lowest energy $e_{2g}$ set comprises two orbitals, $d_{xy}$ and $d_{x^2-y^2}$. These accommodate the first 4 electrons (2 in each orbital). The configuration is $d_{xy}^2 = d_{x^2-y^2}^2$.
  2. The next energy level is the $a_{1g}$ orbital ($d_{z^2}$). It accommodates the next 2 electrons. The configuration is $d_{z^2}^2$.
  3. All 6 electrons have now been placed. The highest energy $e_{1g}$ set, comprising $d_{xz}$ and $d_{yz}$, remains empty. The configuration is $d_{xz}^0 = d_{yz}^0$.

Therefore, the complete electronic configuration is represented as $d_{xy}^2 = d_{x^2-y^2}^2 < d_{z^2}^2 < d_{xz}^0 = d_{yz}^0$.

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