The conic x2 + xy + 2y2 + x + y = 1 is
an ellipse
To identify the type of conic section represented by a general second degree equation, we use the coefficients of the quadratic terms.
The general second degree equation of a conic section is given by:
\(Ax^2 + Bxy + Cy^2 + Dx + Ey + F = 0\)
The given equation is:
\(x^2 + xy + 2y^2 + x + y = 1\)
First, we rewrite the given equation in the standard form \(Ax^2 + Bxy + Cy^2 + Dx + Ey + F = 0\) by moving all terms to one side:
\(x^2 + xy + 2y^2 + x + y - 1 = 0\)
Comparing this with the general second degree equation, we can identify the coefficients:
The type of conic section (non-degenerate) is determined by the value of the discriminant, which is calculated as \(B^2 - 4AC\).
Let's calculate the discriminant for the given equation using the coefficients \(A=1\), \(B=1\), and \(C=2\).
Discriminant \( = B^2 - 4AC \)
\( = (1)^2 - 4(1)(2) \)
\( = 1 - 8 \)
\( = -7 \)
The calculated discriminant is \(-7\). Since \(B^2 - 4AC = -7\), which is less than 0, the equation represents an ellipse (assuming it is not a degenerate case like a point or imaginary ellipse, which is not among the options).
This method provides a straightforward way for conic section identification based purely on the coefficients of the second degree terms in the general second degree equation.
Thus, the type of conic represented by \(x^2 + xy + 2y^2 + x + y = 1\) is an ellipse, according to the rules of analytic geometry for classifying conic sections.
Therefore, the correct classification based on conic section identification using the discriminant is an ellipse.
The equation of an ellipse which has a focus (6, 7), a directix x + y + 2 = 0 and eccentricity \(\frac{1}{{\sqrt 3 }}\), is:
The equation of the tangent at the point (x', y') to the ellipse \(\frac{{{x^2}}}{{{a^2}}} + \frac{{{y^2}}}{{{b^2}}} = 1\) is:
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The equation of sphere is x2 + y2 + z2 - x + z - 2 = 0, its radius is
If the straight line x cosα + y sinα = p is tangent to the ellipse \(\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1\). then