The combined correction for curvature and refraction for a point located at 2 km distance is:
0.2692 m
In surveying, when determining the level of a point, corrections are often needed due to the curvature of the Earth and the refraction of light rays in the atmosphere. These two corrections are often combined into a single value known as the combined correction for curvature and refraction.
The combined correction ($C$) for curvature and refraction can be calculated using an approximate formula when the distance ($D$) is given in kilometers and the result is desired in meters. The formula is:
$\qquad C = 0.0673 \times D^2$
Where:
In this specific question, the distance ($D$) given is 2 km.
Let's substitute the distance value into the formula:
$\qquad C = 0.0673 \times (2 \text{ km})^2$
First, calculate the square of the distance:
$\qquad (2 \text{ km})^2 = 4 \text{ km}^2$
Now, multiply this by the constant 0.0673:
$\qquad C = 0.0673 \times 4$
$\qquad C = 0.2692 \text{ m}$
So, the combined correction for curvature and refraction for a point located at a 2 km distance is 0.2692 meters.
Let's compare our calculated value with the given options:
| Option | Value | Match? |
|---|---|---|
| 1 | 0.2692 m | Yes |
| 2 | 0.1346 m | No |
| 3 | 0.01346 m | No |
| 4 | 0.02692 m | No |
Our calculated combined correction of 0.2692 m matches Option 1.
Using the standard formula for combined correction, $C = 0.0673 \times D^2$, with a distance $D = 2$ km, the resulting combined correction is 0.2692 m. This value represents the total adjustment needed due to the Earth's curvature and atmospheric refraction over that distance.
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