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Question

The combined correction for curvature and refraction for a point located at 2 km distance is:

The correct answer is

0.2692 m

Understanding Combined Correction in Surveying

In surveying, when determining the level of a point, corrections are often needed due to the curvature of the Earth and the refraction of light rays in the atmosphere. These two corrections are often combined into a single value known as the combined correction for curvature and refraction.

Calculating the Combined Correction for 2 km Distance

The combined correction ($C$) for curvature and refraction can be calculated using an approximate formula when the distance ($D$) is given in kilometers and the result is desired in meters. The formula is:

$\qquad C = 0.0673 \times D^2$

Where:

  • $C$ is the combined correction in meters.
  • $D$ is the distance from the instrument to the point in kilometers.

In this specific question, the distance ($D$) given is 2 km.

Let's substitute the distance value into the formula:

$\qquad C = 0.0673 \times (2 \text{ km})^2$

First, calculate the square of the distance:

$\qquad (2 \text{ km})^2 = 4 \text{ km}^2$

Now, multiply this by the constant 0.0673:

$\qquad C = 0.0673 \times 4$

$\qquad C = 0.2692 \text{ m}$

So, the combined correction for curvature and refraction for a point located at a 2 km distance is 0.2692 meters.

Comparing with Options

Let's compare our calculated value with the given options:

Option Value Match?
1 0.2692 m Yes
2 0.1346 m No
3 0.01346 m No
4 0.02692 m No

Our calculated combined correction of 0.2692 m matches Option 1.

Conclusion

Using the standard formula for combined correction, $C = 0.0673 \times D^2$, with a distance $D = 2$ km, the resulting combined correction is 0.2692 m. This value represents the total adjustment needed due to the Earth's curvature and atmospheric refraction over that distance.

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Important Questions from Levelling

  1. The expression for sensitivity of the bubble tube (α) can be taken as, ______

    Where n = No. of divisions, s = Net staff reading, D = Distance, R = Radius of curvature, l = Length of one division

  2. A vertical line which is perpendicular to the level line is called:

  3. In levelling between two points A and B on the opposite sides of a river, the level was first set up near A and the staff readings on A and B were 2.645 m and 2.30 m respectively. The level was then moved near B and set up; the respective staff readings then were 1.085 m and 1.665 m on A and B respectively. What is the true difference of level between A and B?

  4. A level, when set up $20$ m from peg A and $70$ m from peg B, reads $0.750$ m on a staff held on A and $2.065$ m on a staff held on B, keeping the bubble at its centre while reading. If the reduced levels of A and B are $100.500$ m and $101.800$ m respectively, what is the collimation error per $100.0$ m?

  5. In levelling back, sight is also called as ______.

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