The co-effiicent of friction between the road surface and the tyre of an automobile is μ. At what speed v, the automobile can travel safely without skidding around a cur ve of radiu s r. Take m as mass of automobile and g as acceleration due to gravity.
When an automobile travels around a curved road, it requires a centripetal force directed towards the center of the curve to change its direction. This centripetal force is provided by the force of static friction between the tyres of the automobile and the road surface.
The centripetal force (\(F_c\)) required for the automobile to move in a circle of radius \(r\) at a speed \(v\) is given by the formula:
\(F_c = \frac{mv^2}{r}\)
where:
On a level road, the normal force (\(N\)) acting on the automobile is equal to its weight (\(mg\)), where \(g\) is the acceleration due to gravity. The maximum possible force of static friction (\(F_{f,max}\)) between the tyres and the road surface is proportional to the normal force and is given by:
\(F_{f,max} = \mu N\)
Since \(N = mg\) on a level road, the maximum static friction force is:
\(F_{f,max} = \mu mg\)
where \(\mu\) is the coefficient of friction between the road surface and the tyres.
For the automobile to travel safely without skidding around the curve, the required centripetal force must be less than or equal to the maximum static friction force available. The maximum safe speed (\(v_{max}\)) is reached when the required centripetal force is exactly equal to the maximum static friction force:
\(F_c = F_{f,max}\)
\(\frac{mv^2}{r} = \mu mg\)
We can cancel the mass \(m\) from both sides of the equation:
\(\frac{v^2}{r} = \mu g\)
Now, we can solve for \(v^2\):
\(v^2 = \mu g r\)
Taking the square root of both sides to find the maximum safe speed \(v\):
\(v = \sqrt{\mu g r}\)
This equation shows that the maximum safe speed without skidding on a curved road depends on the coefficient of friction (\(\mu\)), the acceleration due to gravity (\(g\)), and the radius of the curve (\(r\)). It does not depend on the mass of the automobile.
Comparing this result with the given options, we find that it matches option 2.
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