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Question

The characteristics equation of the T – FF is given by

The correct answer is \({Q^ + } = T\bar Q + Q\bar T\)

T-FF: Toggle Flip-Flop Basics

A T-FF, short for Toggle Flip-Flop, is a fundamental building block in digital electronics, specifically within sequential circuits. It's essentially a JK flip-flop configured with its J and K inputs connected together. The 'T' in T-FF stands for 'Toggle', highlighting its primary function.

T-FF Operation Explained

The operation of a T-FF is straightforward and depends solely on the value of its input signal, T, and its current state, Q.

  • Hold State: When the input $T = 0$, the flip-flop does not change its state. The next state, $Q^+$, remains the same as the current state, $Q$. Mathematically, $Q^+ = Q$ when $T=0$.
  • Toggle State: When the input $T = 1$, the flip-flop flips its current state. If the current state $Q$ is 0, it becomes 1, and if it is 1, it becomes 0. The next state, $Q^+$, is the inverse of the current state, $Q$. Mathematically, $Q^+ = \bar{Q}$ when $T=1$.

Deriving the T-FF Characteristic Equation

The characteristic equation provides a concise mathematical relationship between the next state ($Q^+$), the current state ($Q$), and the input ($T$). We need an equation that satisfies the conditions described above:

  • $Q^+ = Q$ if $T=0$
  • $Q^+ = \bar{Q}$ if $T=1$

Let's analyze the given options. The correct characteristic equation for the T-FF is:

\({Q^ + } = T\bar Q + Q\bar T\)

This expression is the Boolean form of the Exclusive OR (XOR) operation, often written as $Q^+ = T \oplus Q$. We can verify this equation by substituting the possible values of $T$:

Verification for $T = 0$

When $T=0$, the equation becomes:

\({Q^ + } = (0)\bar Q + Q\overline{(0)}\)

Simplifying this:

\({Q^ + } = 0 + Q(1)\)

\({Q^ + } = Q\)

This result correctly shows that the state remains unchanged ($Q^+ = Q$) when $T=0$.

Verification for $T = 1$

When $T=1$, the equation becomes:

\({Q^ + } = (1)\bar Q + Q\overline{(1)}\)

Simplifying this:

\({Q^ + } = \bar Q + Q(0)\)

\({Q^ + } = \bar Q + 0\)

\({Q^ + } = \bar Q\)

This result correctly shows that the state toggles ($Q^+ = \bar{Q}$) when $T=1$.

T-FF Truth Table

The behavior of the T-FF can also be represented using a truth table:

Input T Current State Q Next State $Q^+$
0 0 0
0 1 1
1 0 1
1 1 0

The characteristic equation $Q^+ = T\bar{Q} + Q\bar{T}$ accurately models this truth table, confirming it as the correct representation for the T-FF.

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Important Questions from Digital Electronics

  1. Latches are _______ circuits.

  2. First generation computers had which of the following?

  3. The 8085 has two registers known as primary data pointers. These are registers

  4. Which of the following is a non-positional number system?

  5. The digital equivalent of an electric series circuit is the:

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