This problem involves calculating the change in brake power of a centrifugal pump when the impeller diameter is altered. We can use the pump affinity laws, specifically the relationship between brake power and impeller diameter.
For a centrifugal pump operating at a constant speed, the brake power ($P$) required is directly proportional to the cube of the impeller diameter ($D$). This can be expressed mathematically as:
$ P \propto D^3 $
Therefore, the ratio of brake power for two different impeller diameters ($D_1$ and $D_2$) is:
$ \frac{P_2}{P_1} = \left(\frac{D_2}{D_1}\right)^3 $
We are given:
We need to find the new brake power, $P_2$. Rearranging the formula:
$ P_2 = P_1 \times \left(\frac{D_2}{D_1}\right)^3 $
Substitute the given values:
$ P_2 = 1.86 \text{ kW} \times \left(\frac{180 \text{ mm}}{200 \text{ mm}}\right)^3 $
First, calculate the ratio of the diameters:
$ \frac{180}{200} = 0.9 $
Now, cube this ratio:
$ (0.9)^3 = 0.729 $
Finally, calculate $P_2$:
$ P_2 = 1.86 \text{ kW} \times 0.729 $
$ P_2 \approx 1.35594 \text{ kW} $
The calculated brake power is approximately 1.356 kW. This value falls within the range of 1.35 kW to 1.36 kW.
A six-stage centrifugal pump delivers 120 L $s^{-1}$ against a total head of 510 m. If the design speed of this pump is 1450 rpm, the specific speed of the pump will be ______________.