The binary number expression of the decimal number 31 is
11111
Numbers can be represented in different number systems. The decimal system (base 10) is what we use in everyday life, using digits 0 through 9. The binary system (base 2) is used by computers, using only digits 0 and 1. Converting a decimal number to its binary equivalent is a fundamental concept in digital electronics and computer science.
To convert a decimal number to its binary representation, we use the method of repeated division by 2. The process involves dividing the decimal number by 2, noting the remainder, and then dividing the quotient by 2. We repeat this until the quotient becomes 0. The binary representation is obtained by reading the remainders from bottom to top.
Let's convert the decimal number 31 to binary:
| Division | Quotient | Remainder |
|---|---|---|
| \(31 \div 2\) | 15 | 1 |
| \(15 \div 2\) | 7 | 1 |
| \(7 \div 2\) | 3 | 1 |
| \(3 \div 2\) | 1 | 1 |
| \(1 \div 2\) | 0 | 1 |
Reading the remainders from bottom (most significant bit) to top (least significant bit), we get the binary number:
11111
Therefore, the binary expression of the decimal number 31 is 11111.
Based on the conversion process, the binary representation of the decimal number 31 is 11111.
| Concept | Description |
|---|---|
| Decimal System | Base 10, uses digits 0-9. Positional system where each digit's value depends on its position multiplied by powers of 10. |
| Binary System | Base 2, uses digits 0 and 1. Positional system where each digit's value depends on its position multiplied by powers of 2. |
| Decimal to Binary | Repeatedly divide the decimal number by 2 and record the remainders. Read remainders bottom-up. |
| Binary to Decimal | Multiply each binary digit by the corresponding power of 2 (starting from \(2^0\) for the rightmost digit) and sum the results. |
In a binary number like \(b_n b_{n-1} ... b_1 b_0\), where \(b_i\) is either 0 or 1, the decimal value is calculated as:
Decimal Value \(= b_n \times 2^n + b_{n-1} \times 2^{n-1} + ... + b_1 \times 2^1 + b_0 \times 2^0\)
For example, in the binary number 11111:
Summing these place values where the digit is '1' gives $16 + 8 + 4 + 2 + 1 = 31$. This confirms the conversion of 11111 binary to 31 decimal.
What is (1110011) 2÷ (10111) 2equal to ?
If x 3 + y 3= (100010111) 2and x + y = (11111) 2, then what is (x - y) 2 + xy equal to ?
The number (1101101 + 1011011) 2can be written in decimal system as
A binary number is represented by (cdccddcccddd) 2, where c > d. What is its decimal equivalent?
The sum of the binary numbers (11011) 2, (10110110)2 and (10011x0y) 2is the binary number (101101101) 2. What are the values of x and y?
The remainder and quotient of the binary division (101110) 2by (110) 2are respectively
In the binary equation (1p101) 2+ (10q1) 2= (100r00) 2
Where p, q and r are binary digits, what are the possible values of p, q and r respectively?If the number 235 in decimal system is converted into binary system, then what is the resulting number?
What is the binary equivalent of the decimal number 0.3125?
What is (1000000001) 2– (0.0101) 2equal to?
Multiplication of 111 2by 101 2is
Let * be binary operation defined on R by \(\rm p * q=\frac{p+q}{2}, \forall \) p, q ∈ R. The operation is:
Convert 29 into binary.
A. 10101
B. 11110
C. 11101
D. 11001
The product of the two binary numbers 011 and 110 is:
If G is the set of integer numbers, and a.b = a – b, ∀ a, b ∈ G, then G is