Average velocity ($\bar{V}$) is defined as the total displacement of an object divided by the total time interval during which the displacement occurred.
Displacement is the change in position of an object, and it is a vector quantity.
The time interval ($\Delta t$) is the difference between the final time ($t_2$) and the initial time ($t_1$).
The formula for average velocity is:
$ \bar{V} = \frac{\text{Displacement}}{\text{Time Interval}} $
Using the notation provided in the options:
Substituting these into the formula gives:
$ \bar{V} = \frac{d}{t_2 - t_1} $
This matches Option 1.
Option 4 ($\frac{S}{\Delta t}$) is also a valid representation where 'S' might represent displacement or distance and '$\Delta t$' is the time interval, but Option 1 specifically uses the variables corresponding to the provided correct answer.
An object is covering distance in direct proportion to the square of time elapsed. What conclusion can be drawn about the motion of the object?
If the distance time graph of the motion of an object is a straight line but not parallel to the time axis, then it may be concluded that the object is moving with a:
Which of the following changes when a body performs uniform circular motion?
Vehicles have treaded tires so that it_______.
The distance time graph for an object, moving with a constant speed will be a