The average salary of employees of a factory is ₹15,000. The average salary of 250 of the employees is ₹16,000 and that of the remaining employees is ₹13,750. Total number of employees in the factory is:
450
This problem involves calculating the total number of employees in a factory based on their average salaries in different groups. We are given the overall average salary, the average salary for a specific number of employees, and the average salary for the remaining employees.
Our goal is to find the total number of employees in the factory.
The average salary is calculated as the total salary divided by the number of employees. We can use this relationship to set up equations. Let's denote:
We know that the total number of employees is the sum of the employees in the two groups:
\[N = n_1 + n_2\]
Also, the total salary of all employees is the sum of the total salaries of the two groups:
\[S = S_1 + S_2\]
The average salary is given by:
\[\text{Average Salary} = \frac{\text{Total Salary}}{\text{Number of Employees}}\]
From this, we can express the total salary as:
\[\text{Total Salary} = \text{Average Salary} \times \text{Number of Employees}\]
Using the given information, we can write the total salaries for each group and the total factory:
Substitute the expressions for \(S\), \(S_1\), and \(S_2\) into the equation \(S = S_1 + S_2\):
\[15000 \times N = (16000 \times 250) + (13750 \times n_2)\]
We also know that \(N = 250 + n_2\). Substitute this into the equation:
\[15000 \times (250 + n_2) = (16000 \times 250) + (13750 \times n_2)\]
Now, we solve the equation for \(n_2\):
First, calculate the product \(16000 \times 250\):
\[16000 \times 250 = 4000000\]
Distribute the 15000 on the left side:
\[15000 \times 250 + 15000 \times n_2 = 4000000 + 13750 \times n_2\]
\[3750000 + 15000 n_2 = 4000000 + 13750 n_2\]
Rearrange the terms to group \(n_2\) on one side and constants on the other:
\[15000 n_2 - 13750 n_2 = 4000000 - 3750000\]
\[1250 n_2 = 250000\]
Now, solve for \(n_2\):
\[n_2 = \frac{250000}{1250}\]
\[n_2 = \frac{25000}{125}\]
\[n_2 = 200\]
So, the number of remaining employees is 200.
The total number of employees is the sum of the first group and the remaining group:
\[N = n_1 + n_2\]
\[N = 250 + 200\]
\[N = 450\]
The total number of employees in the factory is 450.
Let's check if the overall average is correct with 450 employees, 250 at ₹16,000, and 200 at ₹13,750.
Overall average salary = \(\frac{\text{Total Salary}}{\text{Total Number of Employees}} = \frac{6750000}{450}\)
\[\frac{6750000}{450} = \frac{675000}{45}\]
\[\frac{675000}{45} = \frac{135000}{9} = 15000\]
The calculated overall average salary of ₹15,000 matches the given information, confirming our total number of employees is correct.
| Group | Number of Employees | Average Salary (₹) | Total Salary (₹) |
|---|---|---|---|
| Group 1 | 250 | 16,000 | \(250 \times 16000 = 4,000,000\) |
| Remaining Group | \(n_2 = 200\) | 13,750 | \(200 \times 13750 = 2,750,000\) |
| Total Factory | \(N = 250 + 200 = 450\) | 15,000 (Given) | \(4,000,000 + 2,750,000 = 6,750,000\) |
Understanding average calculations is fundamental. Here's a quick review:
| Concept | Formula | Explanation |
|---|---|---|
| Average | \(\frac{\text{Sum of quantities}}{\text{Number of quantities}}\) | Represents the central value of a set of numbers. |
| Total Sum | \(\text{Average} \times \text{Number of quantities}\) | If you know the average and the number of items, you can find the sum. |
| Weighted Average | \(\frac{\sum (w_i \times x_i)}{\sum w_i}\) | Used when different items have different importance or "weights", like calculating the average of groups with different sizes. In our problem, the number of employees in each group acts as the weight. |
Averages are used widely in various fields:
Understanding how to calculate and interpret averages, especially weighted averages as shown in this salary problem, is a key skill in quantitative reasoning.
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