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Question

The armature current of a synchronous motor has large value for-

The correct answer is

Both low and high excitation

Understanding Synchronous Motor Armature Current and Excitation

A synchronous motor is an AC motor that runs at a constant speed, called synchronous speed, determined by the frequency of the power supply and the number of poles in the motor. Unlike induction motors, synchronous motors require a DC excitation voltage applied to their rotor winding. This excitation significantly impacts the motor's performance, particularly its armature current and power factor.

The Relationship Between Excitation and Armature Current

For a synchronous motor operating at a constant mechanical load (output power), changing the DC excitation voltage applied to the rotor field winding affects the armature current drawn from the AC supply. This relationship is graphically represented by the "V-curve" of the synchronous motor.

The V-curve plots the armature current ($I_a$) on the y-axis against the field excitation current (or excitation voltage, representing the strength of the field) on the x-axis, for a constant motor power output.

Analysis Based on the V-Curve

Let's analyze the V-curve to understand how armature current changes with excitation:

  • Medium or Normal Excitation: At a specific level of excitation, the armature current ($I_a$) drawn by the motor is minimum. At this point, the motor operates at unity power factor ($\cos \phi = 1$). This is generally the most efficient operating point for the armature circuit as it minimizes $I^2R$ losses in the armature winding.
  • Low Excitation: If the excitation is decreased below the level corresponding to unity power factor, the synchronous motor becomes "under-excited." In this condition, the motor draws a larger armature current ($I_a$). The motor operates at a lagging power factor. A larger current is needed to maintain the required power output while compensating for the reactive power demand (which is lagging).
  • High Excitation: If the excitation is increased above the level corresponding to unity power factor, the synchronous motor becomes "over-excited." In this condition, the motor again draws a larger armature current ($I_a$). The motor operates at a leading power factor. Here, the motor supplies reactive power to the system, acting like a capacitor, and a larger current is needed to handle this leading reactive power component while still delivering the required real power.

Therefore, the armature current of a synchronous motor is minimum at normal excitation (unity power factor) and increases as the excitation is either decreased (low excitation, lagging PF) or increased (high excitation, leading PF). This means the armature current has a large value for both low and high excitation levels when compared to the minimum value at medium excitation.

Consider a simplified phasor diagram analysis for constant power ($P$) and terminal voltage ($V$). The power is given by $P = \frac{VE}{X_s} \sin \delta$, where $E$ is the excitation voltage (proportional to excitation), $X_s$ is the synchronous reactance, and $\delta$ is the power angle. Also, $V$, $E$, and the voltage drop $I_a X_s$ form a voltage triangle. To maintain constant power $P$ with constant $V$ and $X_s$, as $E$ changes, $\delta$ and $I_a$ must adjust. A larger $I_a$ is required when $E$ is either much smaller or much larger than the value corresponding to minimum $I_a$ (unity PF operation), causing the motor's power factor to deviate significantly from unity (lagging at low E, leading at high E).

Conclusion

Based on the characteristic V-curve of a synchronous motor operating at a constant load, the armature current is minimal at a specific "normal" or "medium" excitation level where the power factor is unity. Any deviation from this optimal excitation level, either towards low excitation (under-excited, lagging PF) or high excitation (over-excited, leading PF), results in an increase in the armature current. Thus, the armature current has a large value for both low and high excitation compared to the minimum value.

The options provided describe the conditions under which the armature current is large:

  1. High excitation
  2. Both low and high excitation
  3. Medium excitation
  4. Low excitation

Based on our analysis of the V-curve, the armature current is large at both low and high excitation.

Excitation Level Motor Condition Power Factor Armature Current ($I_a$)
Low (Under-excited) Acts like a lagging load Lagging ($\cos \phi < 1$) Large
Medium (Normal) Minimum $I_a$ Unity ($\cos \phi = 1$) Minimum
High (Over-excited) Acts like a leading load (capacitor) Leading ($\cos \phi < 1$) Large

Revision Table: Synchronous Motor Excitation and Current

Concept Key Point
Synchronous Motor Runs at synchronous speed, requires DC excitation.
Armature Current ($I_a$) AC current drawn from the supply.
Excitation DC current/voltage applied to the rotor field winding.
V-Curve Graph showing $I_a$ vs. Field Excitation at constant load.
Minimum $I_a$ Occurs at unity power factor (normal/medium excitation).
Large $I_a$ Occurs at low excitation (lagging PF) and high excitation (leading PF).

Additional Information: Synchronous Motor Power Factor Control

One of the key advantages of a synchronous motor is its ability to operate at different power factors simply by changing its DC excitation. This makes them valuable for power factor correction in industrial plants.

  • When a synchronous motor is over-excited (high excitation), it operates at a leading power factor. This means it supplies reactive power to the power system, helping to improve the overall power factor of a plant that may have many induction motors (which consume lagging reactive power).
  • When a synchronous motor is under-excited (low excitation), it operates at a lagging power factor, consuming reactive power from the system, similar to an induction motor.
  • Operating at unity power factor (medium/normal excitation) minimizes armature current and hence minimizes losses within the motor for a given power output. However, operating slightly over-excited to improve plant power factor is a common application.

The magnitude of the armature current is directly related to the reactive power exchange with the grid for a given real power output. For a fixed real power output, a significant reactive power exchange (either consuming or supplying) requires a larger apparent power ($S$) and thus a larger armature current ($I_a$), since $S = V \times I_a$ and $S^2 = P^2 + Q^2$, where $P$ is real power and $Q$ is reactive power.

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Important Questions from Alternator and Synchronous Motors

  1. An alternator has 20 poles and running at 300 RPM will generate alternating voltage and current whose frequency is-

  2. Synchronous motor when used for power factor improvement should be-

  3. In an alternator, the _______ current is generated in the stationary stator.

  4. The speed with which the turbo alternators operate are-

  5. Which of the following are the advantages of distributed armature winding?

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